Vector output from a for loop
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hello everyone,
I have an hourly temperature data which covers 8760 values inside a vector. The TMP shows the temperature values however the values below in the code is just for example since i can't put 8760 values here.
I want to get PGRED results as a vector output too. However, when i run the code, although it calculates PGRED values for all TMP values, i get an answer only for the last TMP value which is 36 in this case. My question is, how can i get all the PGRED answers inside 1 vector.
Thank you for your help in advance.
for TMP =[12, 3, 36]
if TMP < 9
PGRED=0
elseif 9<=TMP & TMP<10
PGRED= TMP-9
elseif 10<=TMP & TMP<28
PGRED= 1
elseif 28<=TMP & TMP<40
PGRED= -0.083*TMP + 3.33
else 40 >= TMP
PGRED=0
end
end
0 commentaires
Réponse acceptée
Raj
le 5 Déc 2019
Modifié(e) : Raj
le 5 Déc 2019
TMP =[12, 3, 36];
PGRED=zeros(size(TMP));
for ii=1:length(TMP)
if TMP(ii) < 9
PGRED(ii)=0;
elseif 9<=TMP(ii) && TMP(ii)<10
PGRED(ii)= TMP(ii)-9;
elseif 10<=TMP(ii) && TMP(ii)<28
PGRED(ii)= 1;
elseif 28<=TMP(ii) && TMP(ii)<40
PGRED(ii)= -0.083*TMP(ii) + 3.33;
else %40 >= TMP(ii) % this condition is not required. Just give a default condition.
PGRED(ii)=0;
end
end
0 commentaires
Plus de réponses (2)
Walter Roberson
le 5 Déc 2019
TMP_values = [12, 3, 36];
num_TMP = length(TMP_values);
PGRED = zeros(1, num_TMP);
for TMP_idx = 1 : num_TMP
TMP = TMP_values(TMP_idx);
if TMP < 9
PGRED(TMP_idx) = 0;
elseif 9<=TMP & TMP<10
PGRED(TMP_idx) = TMP-9;
elseif 10<=TMP & TMP<28
PGRED(TMP_idx) = 1;
elseif 28<=TMP & TMP<40
PGRED(TMP_idx) = -0.083*TMP + 3.33;
elseif 40 >= TMP
PGRED(TMP_idx) = 0;
else
error('Unexpected out of range TMP = %f', TMP)
end
end
This is not what I would recommend for this situation: I would recommend that you learn how to use logical indexing. However, I do recommend that you learn to use this pattern, of storing all of the values in a vector and indexing over the length of the vector and using the index to store the results.
Andrei Bobrov
le 5 Déc 2019
TMP = randi([-12,45],30,4);
f = {@(x)0;@(x)x-9;@(x)1;@(x)3.33 - .083*x;@(x)0};
i = discretize(TMP,[-inf,9,10,28,40,inf]);
out = arrayfun(@(x,y)f{y}(x),TMP,i);
0 commentaires
Voir également
Catégories
En savoir plus sur Matrix Indexing dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!