vectorisation a for loop
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
c=5;
retint=0;
dist=log([10:-1:1]+retint);
for i=1:length(dist)
eta=exp(-c*abs(dist(i)-dist));
discrim(i)=1/sum(eta);
end
Does anyone know how to vectorise this for loop to make it more efficient?
1 commentaire
Stephen23
le 8 Déc 2019
Because you are not concatenating anything, square brackets are not needed here:
dist=log((10:-1:1)+retint);
Réponse acceptée
David Hill
le 8 Déc 2019
Although arrayfun is really a loop,
c=5;
retint=0;
dist=log([10:-1:1]+retint);
discrim=arrayfun(@(x)1/sum(exp(-c*abs(dist-x))),dist);
0 commentaires
Plus de réponses (1)
Stephen23
le 8 Déc 2019
Real vectorized code (no loop or arrayfun):
eta = exp(-c*abs(bsxfun(@minus,dist,dist(:))));
discrim = 1./sum(eta,1)
Or for MATLAB versions >=R2016b:
eta = exp(-c*abs(dist-dist(:)));
discrim2 = 1./sum(eta,1)
0 commentaires
Voir également
Catégories
En savoir plus sur Creating and Concatenating Matrices dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!