Computation's with large numbers.

So, I'm trying to divide n-1( n=94315998522576010519588224930693232398146802027362761139521) by 2^143, I stored n has a symbolic variable to not lose precision, so:

n=sym('94315998522576010519588224930693232398146802027362761139521');

however, when I do n-1/2^143 it gives me a stupid answer 1051658525598479156308916018992636883668880484184809306202701679900748001639266703538773119682234810367/11150372599265311570767859136324180752990208 (the correct answer should be 8458551289020639 ) .

It seems like Matlab has treated n-1/2^143 as a string rather than a computation because it's outputing the / sign.

I've also tried vpa but I encountered the same problem.

Could someone shed a light on this please, how can I compute this without losing accuracy, i.e. preventing Matlab rounding n and my answer.

THANKS!

Answer 1

[JESUS DAVID ARIZA ROYETH]

n=sym('94315998522576010519588224930693232398146802027362761139521');
answer=vpa((n-1)/2^143)

[Yuechuan Chen]

Perfect! Thank you so much!