Heat transfer differential equation

28 vues (au cours des 30 derniers jours)
Enrico Danzi
Enrico Danzi le 10 Déc 2019
Dear all,
I'm quite a new user of Matlab, I'm asking you somethiing that could be simple or obvious, but I've tried and no reasonable results came uot.
I've to calculate the Temperature evolution in time of a system affected by heat conduction and radiation, this is my equation:
eq_heat trasnfer_Enel.png
and this is my attempt code:
function[yp] = f(t,y);
% defining constants
d = 0.00585;
l = 0.03325;
m = 0.009329;
v = 20;
cp = 0.5;
nu = 16.24*10^-6;
sigma = 5.6704*10^-6;
eps = 0.8;
h = (0.26*((d/nu)*v)^0.6)*(0.7^0.37);
A = 7.926*10^-4;
k1 = (h*A)/(m*cp);
k2 = (sigma*eps*A)/(m*cp);
ya = 299;
% equation
yp = k1*(y-ya)+k2*(y^4);
Then, on the command window:
[t,y] = ode45('f',[0,5],1673)
What I am doing wrong (in the problem formulation, I don't care for instance to numbers)?
Thanks for any help!

Réponse acceptée

Enrico Danzi
Enrico Danzi le 10 Déc 2019
I've solved my question using ode113:
[t,y] = ode113(@(t,y) -k1*(y-299)-k2*y^4,[0 100],1673)
, which eventually worked better and did not have any integration step tolerance warnings.
I'll try also your suggestion.
Thanks for your quick reply!

Plus de réponses (1)

darova
darova le 10 Déc 2019
Call the function this way:
[t,y] = ode45(@f,[0,5],1673)

Catégories

En savoir plus sur Heat and Mass Transfer dans Help Center et File Exchange

Produits


Version

R2018a

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by