Interval where values are greater than treshold

1 vue (au cours des 30 derniers jours)
Lucas Russi
Lucas Russi le 10 Déc 2019
Commenté : Lucas Russi le 10 Déc 2019
Hi everyone
Logic = Data > Treshold
I now need to know what the intervals are where the treshold is exceeded
Logic = [1 1 1 0 0 0 1 1 0 1]
Desired_Output = [1 3;7 8;10 10]
So - from 1 to 3, from 7 to 8 aswell as 10
I can't think of a good way to do this.
Thank in advance

Réponse acceptée

Stephen23
Stephen23 le 10 Déc 2019
>> B = find([true;diff(Logic(:))>0]);
>> E = find([diff(Logic(:))<0;true]);
>> M = [B,E]
M =
1 3
7 8
10 10

Plus de réponses (1)

Jeremy
Jeremy le 10 Déc 2019
I believe you are looking for the find command.
find(Logic)
  3 commentaires
Jeremy
Jeremy le 10 Déc 2019
You could use
diff
to determine adjacent numbers and drop the intermediate numbers appropriately
Lucas Russi
Lucas Russi le 10 Déc 2019
Thanks for participating :)
idx = find(Logic)
idx(end+1) = 0
idx(diff(idx) ~= 1)
would be the indices that mark the end of the interval - but what about the start ?

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