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# plot polygon function error

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msh jgtu on 22 Dec 2019
Commented: Matt J on 23 Dec 2019
I want to draw polygon of some data Ki_bounds(:,1) ,Kp_range
I coded polygon function
function polygon( x,y )
function polygon( x,y )
%UNTITLED4 Summary of this function goes here
% Detailed explanation goes here
plot(x,y)
axis([-1 1 -1.6 1])
end
then i called it in main
x=[ Ki_bounds(:,1); flipud(Ki_bounds(:,1))]
y=[Kp_range; flipud(Kp_range);];
poly_set= polygon(x,y);
but it gives error
Error using polygon
Too many output arguments.

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### Answers (1)

David Goodmanson on 22 Dec 2019
Edited: David Goodmanson on 22 Dec 2019
Hi msh,
the reason is pretty simple. You are asking for an output from the function, but you have not provided any in its definition.
Had you written
function z = polygon( x,y )
%UNTITLED4 Summary of this function goes here
% Detailed explanation goes here
plot(x,y)
axis([-1 1 -1.6 1])
z = (whatever)
end
then the call would have worked. Or you can leave the function as is and just call it:
polygon(x,y)

#### 1 Comment

Matt J on 23 Dec 2019
msh jgtu's answer converted to comment:
yes the function works without using z, the problem came when i use poly_set= polygon(x,y)
i want to use the polygon in Math operation so i used polyset this gives the error

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