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Convert Nx1 matrix into a single number

16 vues (au cours des 30 derniers jours)
Krzysztof Mazur
Krzysztof Mazur le 3 Jan 2020
Modifié(e) : Adam Danz le 3 Jan 2020
I need to convert many Nx1 matrices into simple intergers. Example:
A=[1 2 3 4 5];
And what I need:
It isn't a problem to make it manually with small matrices, but mines are bigger than 100x1. Can someone help me?
  1 commentaire
Stephen23 le 3 Jan 2020
Modifié(e) : Stephen23 le 3 Jan 2020
"I need to convert many Nx1 matrices into simple intergers. ...but mines are bigger than 100x1"
Well that is not going to work. Simple integers only go up to
>> intmax('uint64')
ans = 18446744073709551615
which has exactly 20 digits. If you want to store more than twenty digits, then you cannot use simple integers: you could use character vectors, symbolic integers, or use a special class, e.g.:

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John D'Errico
John D'Errico le 3 Jan 2020
Modifié(e) : John D'Errico le 3 Jan 2020
There are probably a gajillion ways to do this trivially.
Since A is a vector of numeric digits, stored as numbers, the simplest is to just use them as numbers. The nice thing is, it will be efficient, and very fast. (Possibly more so than converting them to chars, as others might have you do.) Thus...
A = [1 2 3 4 5];
B = dot(A,10.^(numel(A)-1:-1:0));
B =
Or, one could use tools like base2dec, str2double, str2num, eval, etc. Personally, my favorite from that list might be the short...
base2dec(A +'0',10)
ans =
Having said that, you will not be able to do so, not for numbers with more than 15 digits in general. (You can suceed with SOME 16 digit numbers, but not even most such numbers.) However, you are talking about doing so with 100 digit numbers. A double in MATLAB cannot represent numbers larger than 2^53-1 exactly as integers.
So if you absolutely need to do this, then you absolutely need to use some tool that will allow you to work with large integers. The problem is, those tools are relatively slow. (I'm saying this even about my own VPI tool, as the author.) And then, even then you will be converting those numbers back and forth from a ilst of individual digits to work with them. Instead, you will be far better off if you learn to work with those lists of digits as a list of digits.

Plus de réponses (2)

Max Murphy
Max Murphy le 3 Jan 2020
A=[1 2 3 4 5];
  4 commentaires
Max Murphy
Max Murphy le 3 Jan 2020
Thanks! But I think Stephen raises a good point- I missed that you might have more than 100 digits, in which case my answer would cause an overflow.
Stephen23 le 3 Jan 2020
Modifié(e) : Stephen23 le 3 Jan 2020
Note that this is limited to 16 digits or so, otherwise you will lose information:
>> A = randi(9,1,17)
A =
3 6 5 4 8 6 5 9 3 7 7 4 6 1 1 5 8
>> B = str2double(sprintf('%g',A))
B =
>> fprintf('%.0f\n',B)
>> fprintf('%lu\n',B)
Also note that the question specified up to 100 digits. There is no way to make this answer work keeping all 100 digits of information.

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Adam Danz
Adam Danz le 3 Jan 2020
Modifié(e) : Adam Danz le 3 Jan 2020
Produce an input vector of 100 single digits
A = randi(9,1,100); % 100 random integers 1:9
% Example: [5 9 2 9 4 5 ... ]
Convert to a character array of 100 characters without spaces
Achar = regexprep(num2str(A),' *','')
% Example: '592945725863239255999239175....'
Or, convert to a large integer
Adouble = str2double(regexprep(num2str(A),' *',''))
% Example: format long; 5.929457258632392e+99
Note that the number must be less than intmax('uint64') as mentioned by Stephen Cobeldick.


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