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how can i print all the data from a computation in one line?

1 vue (au cours des 30 derniers jours)
jelly
jelly le 5 Oct 2012
how can i do this? ex.
"for i=1:3
end"
desired output: i=[1 2 3] or i=123
..
ex.two
" x=input('input value of x: ') %then the user will enter x=[1:5]
y=x.*2;"
desired output: y=[2 4 6 8 10] or y=246810
..
ex three
N=35
while N>=2
A=rem(N,2)
N=floor(N/2)
end
and my desired output is A=11000 or A=[1 1 0 0 0]
how could i do this?

Réponses (3)

Thomas
Thomas le 5 Oct 2012
Modifié(e) : Thomas le 5 Oct 2012
ii=1:3
or
ii=[1:3]
  8 commentaires
jelly
jelly le 6 Oct 2012
Hey tom, yes this is really what i need, finally someone get what i mean, HAHA, thankyou for spending time understanding my problem, thanks bro.
Walter Roberson
Walter Roberson le 6 Oct 2012
You will find that this code will not print the result on one line at some point around 2^19 to 2^24 (depending exactly how wide your command window is set to.) Instead you will get a display such as
A =
Columns 1 through 18
0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Columns 19 through 20
0 0
The output for A will also not have the [] that you required when there were spaces between the elements.
You can fix both of those problems by not displaying A and instead displaying
mat2str(A)

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Image Analyst
Image Analyst le 5 Oct 2012
If you're going to allow the user to enter brackets and colons, then you're going to have to accept it as a string and either call eval(), or parse the string to extract out the individual numbers.

Walter Roberson
Walter Roberson le 5 Oct 2012
N=35
fprintf('%s', 'A=');
while N>=2
A=rem(N,2);
fprintf('%d', A);
N=floor(N/2);
end
fprintf('\n')
Note that your logic will fail to print the last binary digit.

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