how to read complex file data to matrix
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
vincent lin
le 17 Jan 2020
Modifié(e) : per isakson
le 18 Jan 2020
I have a.txt file, with complex data. the format is
1.958138021e-02 0.64646110658609712285 + 0.093290941560866688653j
1.958139648e-02 0.32117256288141476928 - 0.061542254916540022058j
1.958141276e-02 -0.22359569118086644601 + 0.3585713533321416846j
1.958142904e-02 -0.22397218216792619261 + 0.082213621398327246803j
1.999960938e-02 0
1.999962565e-02 0
1.999964193e-02 0
1.999965820e-02 0
2.000000000e-02 0.10412797744247889731 + 0.0081123700776114041067j
There's space between + and -. how can I read this file into a matrix with seperated I part and Q part.
like
1.958138021e-02 0.64646110658609712285 0.093290941560866688653
...
1.999960938e-02 0 0
2.000000000e-02 0.10412797744247889731 0.0081123700776114041067
2 commentaires
Réponse acceptée
per isakson
le 17 Jan 2020
Following Walter's advise
%%
chr = fileread('a.txt');
%%
chr = strrep( chr, ' + ', '+' );
chr = strrep( chr, ' - ', '-' );
cac = textscan( chr, '%f%f' );
%%
M = cat( 2, cac{1}, real(cac{2}), imag(cac{2}) );
>> M(1:3,:)
ans =
0 0.10413 0.0081124
1.6276e-08 -0.04608 -0.073765
3.2552e-08 -0.038321 0.076231
1 commentaire
Plus de réponses (1)
Walter Roberson
le 17 Jan 2020
Sometimes easiest is to read the file as a character vector, use regexp to remove the space around the sign of the imaginary part, and then textscan. textscan and other numeric formats can read complex values when there is no space.
Or read the file as string and regexp to change lines that do not end in j to append + 0j on them. With all lines having the same format you can easily textscan to extract real and imaginary separately.
0 commentaires
Voir également
Catégories
En savoir plus sur Data Type Conversion dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!