create a vector without for

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vincent lin
vincent lin le 19 Jan 2020
Commenté : Stephen23 le 19 Jan 2020
The vector structure is like [a b c d e f g h i j]
a=1:10
b=1:10
...
j=1:5
vect=[]
I can use for a =1:10
for b=1:10
...
vect = [vect;a.b...j]
end
end
but it looks not elegant. Is there a better way to generate it?
  8 commentaires
vincent lin
vincent lin le 19 Jan 2020
Thanks David. My question is a general question and no specific application. I can reduce it to [a b c d] for example.
a=1:10
b=1:10
c=1:3
d=1:5
Total array size is 10*10*3*5. So Yes, I'd like to have possible permutation. I can use for commands but it will need several for. If there're other more compact ways to generate these vectors, that would be good.
Stephen23
Stephen23 le 19 Jan 2020
"I'd like to have possible permutation"
Then you should have asked about generating permutations: http://xyproblem.info/

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Réponse acceptée

Walter Roberson
Walter Roberson le 19 Jan 2020
a=1:10;
b=1:10;
c=1:3;
d=1:5;
[A, B, C, D] = ndgrid(uint8(a), uint8(b), uint8(c), uint8(d)) ;
v = [A(:), B(:), C(:), D(:)] ;

Plus de réponses (1)

Image Analyst
Image Analyst le 19 Jan 2020
Try
a = 1 : 10
b = 1 : 10
...
j = 1 : 5
outputVector = [a, b, c, d, e, f, g, h, i, j]

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