Getting the max value of a certain column, fetching the entire row from a 3D matrix and write those in a new matrix

1 vue (au cours des 30 derniers jours)
Hi,
I have a 3D matrix Once_Still_3D of form 68 x 8 x 30, with 30 being the timesteps. I need to find the max value of column 3 from each timestep, fetch the corresponding row and put the row in a new matrix where the row index is same as the timestep index of the 3D matrix.
for k=1:30
[~,idx]=max(Once_Still_3D(:,3,k));
Out(k,:)=Once_Still_3D(idx,:,k);
end
Using this code results in repetition of values found with k=1 in the output file Out.
Here's the output:
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
113.500000000000 68 0.172359450012208 0.0262343597381685 0 0 0 0
Kindly help.
  2 commentaires
Sindar
Sindar le 20 Jan 2020
To me, this looks like it should work. I'd check your data. Does Once_Still_3D(:,3,1) look different from Once_Still_3D(:,3,2)?
Arup Bhattacharya
Arup Bhattacharya le 20 Jan 2020
Yes, matrices for all the timesteps are different. I am also trying to figure this out whether there is a problem with the 3D matrix or whether the max values everywhere is same.

Connectez-vous pour commenter.

Réponses (1)

KSSV
KSSV le 20 Jan 2020
A = rand(68,8,30) ; % randmom data for demo
col = 3 ; % third column from which max to be seeked
[m,n,p] =size(A) ; % dimensions
iwant = zeros(p,n) ; % initialze the required
for i = 1:p
[val,id] = max(A(:,3,i)) ;
iwant(i,:) = A(id,:,i) ;
end

Catégories

En savoir plus sur Logical dans Help Center et File Exchange

Produits

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by