optimization with sqp algorithm

4 vues (au cours des 30 derniers jours)
Sarah Kern
Sarah Kern le 27 Jan 2020
Commenté : Alan Weiss le 29 Jan 2020
Why doesnt the sqp algorithm works on my oprimization problem?
function [ Fx1, Fx2, Fx3, Fx4, alpha1, alpha2, alpha3, alpha4] = fcn(Fx_v, Fy_v, Mz_v, P_max_1, P_max_2, P_max_3, P_max_4, M_reg_1, M_reg_2, M_reg_3, M_reg_4, k, delta_T_aA, SW_1, SW_2, SW_3, SW_4, w_1, w_4, w_3, w_2, d_delay_1, d_delay_2, d_delay_3, d_delay_4, r_dyn_1, r_dyn_2, r_dyn_3, SOC_1, SOC_2, r_dyn_4, SOC_3, SOC_4, f_lag, n, j,w_vr, w_vl, w_hr, w_hl, l_h, l_v, c_w,d_min_vl, d_max_vl, d_min_vr, d_max_vr, d_min_hl, d_max_hl, d_min_hr, d_max_hr, A, B, FxB_max, SOC_krit, C, x0)
fun = @(x) C*((Fx_v-(x(1)*cos(x(5)+SW_1)+x(2)*cos(x(6)+SW_2)+x(3)*cos(x(7)+SW_3)+x(4)*cos(x(8)+SW_4)-x(5)*sin(x(5)+SW_1)*c_w-x(6)*sin(x(6)+SW_2)*c_w-x(7)*sin(x(7)+SW_3)*c_w-x(8)*sin(x(8)+SW_4)*c_w))^2+ (Fy_v-(x(1)*sin(x(5)+SW_1)+x(2)*sin(x(6)+SW_2)+x(3)*sin(x(7)+SW_3)+x(4)*sin(x(8)+SW_4)+x(5)*cos(x(5)+SW_1)*c_w+x(6)*cos(x(6)+SW_2)*c_w+x(7)*cos(x(7)+SW_3)*c_w+x(8)*cos(x(8)+SW_4)*c_w))^2+ (Mz_v-(x(1)*(-cos(x(5)+SW_1)*w_vl+l_v*sin(x(5)+SW_1))+x(2)*(cos(x(6)+SW_2)*w_vr+sin(x(6)+SW_2)*l_v)+x(3)*(-cos(x(7)+SW_3)*w_hl-l_h*sin(x(7)+SW_3))+x(4)*(cos(x(8)+SW_4)*w_hr-sin(x(8)+SW_4)*l_h)+x(5)*(sin(x(5)+SW_1)*c_w*w_vl+cos(x(5)+SW_1)*c_w*l_v)+x(6)*(-sin(x(6)+SW_2)*c_w*w_vr+cos(x(6)+SW_2)*c_w*l_v)+x(7)*(sin(x(7)+SW_3)*c_w*w_hl-cos(x(7)+SW_3)*c_w*l_h)+x(8)*(-cos(x(8)+SW_4)*c_w*l_h-sin(x(8)+SW_4)*c_w*w_hl)))^2); %(f_lag >= 0).*((A/SOC_1)*(x(1))^2+(A/SOC_2)*(x(2))^2+(A/SOC_3)*(x(3))^2+(A/SOC_4)*(x(4))^2+(d_delay_1-(SW_1+x(5)))^2+(d_delay_2-(SW_2+x(6)))^2+(d_delay_3-(SW_3+x(7)))^2+(d_delay_4-(SW_4+x(8)))^2) + (f_lag == -1).*((((B*(M_reg_1/(M_reg_1+M_reg_2+M_reg_3+M_reg_4)))/SOC_1)*(1/(x(1)^2)))+(((B*(M_reg_2/(M_reg_1+M_reg_2+M_reg_3+M_reg_4)))/SOC_2)*(1/(x(2)^2)))+(((B*(M_reg_3/(M_reg_1+M_reg_2+M_reg_3+M_reg_4)))/SOC_3)*(1/(x(3)^2)))+(((B*(M_reg_4/(M_reg_1+M_reg_2+M_reg_3+M_reg_4)))/SOC_4)*(1/(x(4)^2)))+(d_delay_1-(SW_1+x(5)))^2+(d_delay_2-(SW_2+x(6)))^2+(d_delay_3-(SW_3+x(7)))^2+(d_delay_4-(SW_4+x(8)))^2);
A = [];
b = [];
Aeq = [ 0 0 0 0 0 0 0 0; 0 0 0 0 0 0 0 0];
if f_lag == -1
%if it is possible the regenerative braking torque is the limit
% sum of the Force from the regenerative braking torque in vehiclecoordinates is bigger than the demanded force for the whole vehicle
% M_reg is always positive and Fx_v can be either positive or negative in the braking case
if (cos(SW_1)*(M_reg_1/r_dyn_1)+cos(SW_2)*(M_reg_2/r_dyn_2)+cos(SW_3)*(M_reg_3/r_dyn_3)+cos(SW_3)*(M_reg_4/r_dyn_4))> abs(Fx_v)
% max. regenerative braking torque
lb = [-M_reg_1/r_dyn_1, -M_reg_2/r_dyn_2, -M_reg_3/r_dyn_3, -M_reg_4/r_dyn_4, d_min_vl-SW_1, d_min_vr-SW_2, d_min_hl-SW_3, d_min_hr-SW_4]; %d and betato the left side are positive, to the right side are negative %regenerative braking torque must be positive
ub = [M_reg_1/r_dyn_1, M_reg_2/r_dyn_2, M_reg_3/r_dyn_3, M_reg_4/r_dyn_4, d_max_vl-SW_1, d_max_vr-SW_2, d_max_hl-SW_3, d_max_hr-SW_4];
else
% mechanical braking
%FxB_max is positive
lb = [-FxB_max, -FxB_max, -FxB_max, -FxB_max, d_min_vl-SW_1, d_min_vr-SW_2, d_min_hl-SW_3, d_min_hr-SW_4]; %d and betato the left side are positive, to the right side are negative %FxB_max is negative
ub = [FxB_max, FxB_max, FxB_max, FxB_max, d_min_vl-SW_1, d_min_vr-SW_2, d_min_hl-SW_3, d_min_hr-SW_4];
end % close conditions for braking loop, max braking torque is positive
%driving mode
else
lb = [-P_max_1/(r_dyn_1*w_1), -P_max_2/(r_dyn_2*w_2), -P_max_3/(r_dyn_3*w_3), -P_max_4/(r_dyn_4*w_4), d_min_vl-SW_1, d_min_vr-SW_2, d_min_hl-SW_3, d_min_hr-SW_4];
ub = [P_max_1/(r_dyn_1*w_1), P_max_2/(r_dyn_2*w_2), P_max_3/(r_dyn_3*w_3), P_max_4/(r_dyn_4*w_4), d_max_vl-SW_1, d_max_vr-SW_2, d_max_hl-SW_3, d_max_hr-SW_4];
end
%ub = (1:8);
nlcon = @nonlnconstraints;
%options = optimoptions(@fmincon, 'MaxFunctionEvaluations',10.000000e+03);
options = optimoptions(@fmincon, 'Algorithm', 'sqp');
x = fmincon(fun,x0,A,b,Aeq,beq,lb,ub,nlcon(Fx_v,Fy_v,Mz_v,SW_1,SW_2,SW_3,SW_4,w_vr, w_vl, w_hr, w_hl, l_h, l_v, c_w),options);
the problem works with the interior point algorithm, but the matlab function block, wont let me use it.
Any ideas, how I can make my problem work with the sqp algorithm?
Thank you very much!
  2 commentaires
Matt J
Matt J le 27 Jan 2020
How do we know that sqp doesn't work?
Alan Weiss
Alan Weiss le 29 Jan 2020
Why do you have an all-zero Aeq? Looks like a mistake. And I don't see your definition of beq.
Alan Weiss
MATLAB mathematical toolbox documentation

Connectez-vous pour commenter.

Réponses (0)

Catégories

En savoir plus sur Energy Storage dans Help Center et File Exchange

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by