Arguments block syntax not being recognised

14 vues (au cours des 30 derniers jours)
Will Hardiman
Will Hardiman le 31 Jan 2020
Commenté : sepand soltani le 23 Déc 2021
I'm trying to use an arguments block for input argument validation in a standalone function. I followed the instructions here, and even tried copying the forwardSpeed example:
function forwardSpeed(a,b,c)
arguments
a double
b char
c SpeedEnum
end
% Function code
disp(class(a)) % Line 9 (where the error is located)
disp(class(b))
disp(class(c))
end
however the editor does not highlight the syntax properly, and when I try to run it, I get the following error:
>>forwardSpeed(1,'a',2)
Error: File: /home/$USER/forwardSpeed.m Line: 9 Column: 5
This statement is not inside any function.
(It follows the END that terminates the definition of the function "forwardSpeed".)
The output for my MATLAB version:
>>version
ans =
'9.6.0.1214997 (R2019a) Update 6'

Réponse acceptée

Adam
Adam le 31 Jan 2020
Modifié(e) : Adam le 31 Jan 2020
This was only introduced in 2019b (you can see at the bottom of the help page for 'arguments'). It is one of the disadvantages of using the online help (which is always for the latest version) rather than your offline help (which is for your version).
You can use
doc validateattributes
to achieve similar though, which is what I have been doing the past many years.
  4 commentaires
Neon Argentus
Neon Argentus le 9 Avr 2020
I found the problem.
Before the arguments statement, there should be no codeword. Otherwise it works.
sepand soltani
sepand soltani le 23 Déc 2021
I had the same problem. thanks 👍

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