how to replace missing values from a double inside a cell array?

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Farshid Daryabor
Farshid Daryabor le 5 Fév 2020
Commenté : BN le 5 Fév 2020
I really thanks in advance anybody can tell me how can I replace THE missing values (100000) in the below cell array with NaN.
A = {[1,2,3,100000,4,5,100000],[6,100000,7,100000]};

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JESUS DAVID ARIZA ROYETH
JESUS DAVID ARIZA ROYETH le 5 Fév 2020
newA=cellfun(@(x) x.*(x~=100000)./(x~=100000),A,'Uni',false)

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BN
BN le 5 Fév 2020
Modifié(e) : BN le 5 Fév 2020
index=find(A==100000); %found 100000 in the A
A(index)=NaN; % Replace them by NaN
  2 commentaires
JESUS DAVID ARIZA ROYETH
JESUS DAVID ARIZA ROYETH le 5 Fév 2020
'==' does not work with argument of type cell
BN
BN le 5 Fév 2020
Dear JESUS,
You are right, It's my bad. Thank you for letting me know

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