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how to plot 3rd order differential equation in Matlab?

3 vues (au cours des 30 derniers jours)
Joy Salomi
Joy Salomi le 13 Fév 2020
Commenté : Joy Salomi le 16 Fév 2020
Hello,
What is wrong in this coding? I got some error. Please help me in this. I have attached the problem and code below. Thanks in advance.
My equation and bcs are:
f'''+f f'' -1.3333 (f')^2 - f' = 0
f(0)=0 , f'(0)=1 , f'(infinity)=0
function heattransfernew
options=bvpset('stats','off','RelTol',1e-6);
solinit=bvpinit(linspace(0,6,20),[0,6]);
sol=bvp4c(@f, @OdeBC, solinit, options);
plot(sol.x,sol.y(1,:));
end
function dydx = f(x,y)
dydx(1) = y(2);
dydx(2) = y(3);
dydx(3) = -y(1).*y(3)+1.3333.*(y(2).^2)+y(2);
end
function res = OdeBC(ya,yb)
res = [ya(1)
ya(2)-1
yb(2)
];
end

Réponses (1)

darova
darova le 13 Fév 2020
Where is 3d initial condition?

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