Selecting parts of gridded data- I Need Help. I want to know it's possible or not?
3 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hey all hope you have a good time,
I have a (1 x 1171) cell which includes tables. Each table has a specific latitude and longitude (columns). All 1171 tables latetudes and longitudes together represent gridded precipitation data over the whole country in the 0.5 x 0.5 degree (longitude x latitude).
I also have some points data (in the form of a table with columns of longitude, latitude, and precipitation).
I want to delete each grid in my cell that doesn't have at least one of my points inside it.
For example: If red dots are my points (in the table that I mentioned above), I want to keep each grid that has at least one red dot inside it (I would like to keep grid if more than one point is in it). So from 130 grids in this figure below I want to keep only nine grids that have points. So if my cell was 130x336 now it is just 9x336.
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/272011/image.jpeg)
I attach my cell and my points.
Thank you so much for your valuable advice.
3 commentaires
Réponse acceptée
darova
le 17 Fév 2020
Here is my achievement
clc,clear
load points.mat
load grid_datamat.mat
p = table2array(Points);
g = table2array(grid_data(:,2:3));
x = floor( (p(:,2)-24.25)/0.5 )*0.5+24.25;
y = floor( (p(:,3)-44.25)/0.5 )*0.5+44.25;
plot(p(:,2),p(:,3),'.r')
hold on
plot([x x+0.5 x+0.5 x x]',[y y y+0.5 y+0.5 y]','.-b','markersize',15)
plot(g(:,2),g(:,1),'.g')
hold off
7 commentaires
darova
le 18 Mar 2020
I believe it happens because of new mesh (0.025)
>> g(1,:)
ans =
44.0250 24.0250
Little improvement
x0 = g(1,2) + 0.25;
y0 = g(1,1) + 0.25;
x = floor( (p(:,2)-x0)/0.5 )*0.5+x0;
y = floor( (p(:,3)-y0)/0.5 )*0.5+y0;
looks equal
![](https://www.mathworks.com/matlabcentral/answers/uploaded_files/277884/image.png)
Plus de réponses (0)
Voir également
Catégories
En savoir plus sur Surface and Mesh Plots dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!