x for y is?

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jop schilder
jop schilder le 24 Fév 2020
Commenté : jop schilder le 24 Fév 2020
my data is a table of 17439x3. With the lines being: time, displacement and force, respectively.
I Need all the corresponding values for time and displacement at the peak forces.
my code is
[pks] = findpeaks (-M2B{:,3},'MinPeakProminence',4);
pks = -pks;
idx = find(M2B{:,3} == pks(:,1);
loc = M2B{:,2}(idx);
this does however not work, if i insert pks (1,1) it does work but i dont get it to work for all values. Can anybody help?

Réponse acceptée

Matt J
Matt J le 24 Fév 2020
[pks,idx] = findpeaks (-M2B{:,3},'MinPeakProminence',4);
pks = -pks;
peak_time=M2B{idx,1};
peak_displacement=M2B{idx,2};
  1 commentaire
jop schilder
jop schilder le 24 Fév 2020
Thanks!

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