hi,Can i divide the matrix into layers ,outer layer(boundary elements)then second layer and so on.
for example
original matrix is
1 2 3 4 5 6 7 8
9 10 11 12 13 14 15 16
17 18 19 20 21 22 23 24
25 26 27 28 29 30 31 32
33 34 35 36 37 38 39 40
41 42 43 44 45 46 47 48
49 50 51 52 53 54 55 56
57 58 59 60 61 62 63 64
After one bit right shift of outside boundary and inside layers (its like contour)
9 1 2 3 4 5 6 7
17 18 10 11 12 13 14 8
25 26 27 19 20 21 15 16
33 34 35 36 28 22 23 24
41 42 43 37 29 30 31 32
49 50 44 45 46 38 39 40
57 51 52 53 54 55 47 48
58 59 60 61 62 63 64 56

 Réponse acceptée

David Hill
David Hill le 29 Fév 2020

0 votes

Not sure if there is an easier way, but this does it for you.
function M=matShift(M)
x=size(M,1);
for k=1:floor(x/2)
z=x-2*(k-1)-1;
y=circshift([M(k,k:end-k),M(k:end-k,end-k+1)',M(end-k+1,end-k+1:-1:k+1),M(end-k+1:-1:k+1,k)'],1);
M(k,k:end-k)=y(1:z);
M(k:end-k,end-k+1)=y(z+1:2*z);
M(end-k+1,end-k+1:-1:k+1)=y(2*z+1:3*z);
M(end-k+1:-1:k+1,k)=y(3*z+1:4*z);
end

4 commentaires

sadiqa ilyas
sadiqa ilyas le 29 Fév 2020
It works .Thank you so much
sadiqa ilyas
sadiqa ilyas le 29 Fév 2020
so how to get the original matrix back
Just assign to a different variable at beginning
m=M;
sadiqa ilyas
sadiqa ilyas le 1 Mar 2020
thanks

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