Hi
I am trying to do the following calululation in matlab:
But I do not how how to do the two sums in the front. Our data (d) is a 67x120 array.
Any suggestions would be appreciated :)

2 commentaires

darova
darova le 2 Mar 2020
Luna
Luna le 2 Mar 2020
Modifié(e) : Luna le 2 Mar 2020
What have you done so far as coding? And what is d?

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 Réponse acceptée

Guillaume
Guillaume le 2 Mar 2020
Modifié(e) : Guillaume le 2 Mar 2020

1 vote

s = (1:size(d, 1)).';
result = sum(sum(d .* cos(s))) / sum(cos(s));
Loops not needed, they're just a waste of time.

3 commentaires

Luna
Luna le 2 Mar 2020
Modifié(e) : Luna le 2 Mar 2020
My understanding of /Sigma[cos(s)] part, it should be divided into sum of cos(s) from 1 to what s is until that iteration. For example if s is 20 while j = 3;
d(20,3)*cos(20) / ( cos(1)+cos(2)+...+cos(20) )
so your result gives a vector (1x67). I assume that result must be a scalar.
Yes, I made a mistake, there was a sum missing in the denominator. I assumed that the could be taken out of the double sum, i.e. it's over the whole range. It's not clear and we didn't get an answer to Darova's question. So, my code implement:
If it's a partial sum as you think, then:
s = (1:size(d, 1)).';
result = sum(sum(d .* cos(s) ./ cumsum(cos(s))));
which implements
Luna
Luna le 3 Mar 2020
You are right.

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Plus de réponses (1)

Luna
Luna le 2 Mar 2020

0 votes

Maybe something like that would help:
d = rand(67,120);
sum_of_cos_s = 0;
result = 0;
for s = 1:67
for j = 1:120
sum_of_cos_s = sum_of_cos_s+cos(s);
result = result + (d(s,j)*cos(s))/sum_of_cos_s;
end
end

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