convert double to signed int

Hi,

Some doubt: if A=40000 = 0x9C40 and I'd like that 0x9C40 would be as signed integer - what shall be done?

executing int16, I'm getting

int16(A) = 32767

Any suggestion so that I'll get -25,536‬ ?

Answer 1

[Walter Roberson]

Depending on how the input is stated...

value = 0x9C40s16

value = int16 -25536

Answer 2

[BhaTTa]

To interpret 0x9C40 as a signed 16-bit integer (which in two's complement would indeed be -25536), you can follow this approach:

1. Direct Interpretation (If the number is already in two's complement): If you have a number that is already in a form of two's complement (like 0x9C40 for a 16-bit system) and you want to interpret it as a signed integer, you can do the following:

% Your hexadecimal value
hexVal = '9C40';

% Convert hex to a 16-bit signed integer
signedVal = typecast(uint16(hex2dec(hexVal)), 'int16');

% Display the result
disp(signedVal);

This code snippet uses hex2dec to convert the hexadecimal string to a decimal. Since hex2dec returns a number that doesn't have a sign, it's first considered as uint16 (unsigned 16-bit integer). The typecast function is then used to reinterpret this number as int16 without changing its bit representation, allowing it to be interpreted as a signed integer.

Answer 3

[Stephen23]

A = 40000

A = 40000

B = typecast(uint16(A), 'int16')

B = int16 -25536