Placing and labeling ROIs on an image

Hi!

I'm looking to place ROI circles of the same size on about 5-10 coordinate points in an image.

So far, I've extracted and plotted the coordinates of these points by clicking on them with crosshairs:

imshow(Image,[]);
set(gcf, 'units','normalized','outerposition',[0 0 1 1]); %For fullscreen
[x, y] = getpts; % I know this function isn't recommended any more, any better ideas?
hold on
plot(x, y, 'o', 'MarkerSize', 5, 'MarkerEdgeColor','green', 'MarkerFaceColor','green');
hold off

(Green dots in the image)

What I'd like to do further is to place circle ROIs of a specific radius on each dot, and create a mask with each circle ROI separately, retaining its specific coordinate information.

It would be ideal to have labels for each circle ROI on the final image.

I look forward to hearing your suggestions!

Thanks,

Veena

[Image Analyst]

Where do you want to place the circles? Where the user clicks? Random locations? Some locations determined from the image content?

Anyway, once you have the locations decided upon, you can either use

plot(x, y, 'ro', 'MarkerSize', 30);

and change the MarkerSize to whatever you want.

Or else to get exact radii in pixels, use the FAQ: https://matlab.fandom.com/wiki/FAQ#How_do_I_create_a_circle.3F

[Veena Chatti]

I have been working some more on this.

Now I can get it to place the ROIs on the specified coordinates, but somehow, I can't get it to save an image with all the ROIs. It only saves the last one. I feel like it's something really simple I'm missing with this loop:

Labels = int2str(coordinates(:,3));

for q = 1:length(coordinates)
    imshow(merge,[]);
    hold on
    set(gcf, 'units','normalized','outerposition',[0 0 1 1]);
    h(q) = drawcircle('Center', [x(q), y(q)], 'Radius', 5, 'InteractionsAllowed', 'none');
    mask = h(q).createMask;
    m = mask(mask>0);
    hold off    
end
saveas(gcf, Labels(2, 1:3), 'jpg')

This saves an image that looks like this:

(Note just the one blue circle representing my ROI, the last one in the loop.)

Thanks so much for all your help!