average each block of class in a matrix

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alessio tugnolo
alessio tugnolo on 16 Mar 2020
Edited: Guillaume on 16 Mar 2020
Hi, I have a large matrix where the rows are labelled according to different classes. I would like to obtain an average row of each class. How can I do it?
Thank you!

Accepted Answer

Guillaume on 16 Mar 2020
Edited: Guillaume on 16 Mar 2020
It's unclear how your input data is actually stored in matlab so please clarify if the below doesn't apply.
I'm assuming that you have a two column matrix with one column storing the the class and the other the column storing the values you want to average by class. In this case, this is trivially achieved with groupsummary:
classcolumn = 1; %change as appropriate
valuecolumn = 2; %can be more than one column. Each column will be average by class
classmean = groupsummary(yourmatrix, classcolumn, 'mean', valuecolumn);
Other simple ways this can be achieved: splitapply or accumarray:
classcolumn = 1;
valuecolumn = 2;
group = findgroups(yourmatrix(:, classcolumn));
classmean = splitapply(@mean, yourmatrix(:, valuecolumn), group);
classmean = accumarray(group, yourmatrix(:, valuecolumn), [], @mean); %this one can only work on one column though

More Answers (1)

Sriram Tadavarty
Sriram Tadavarty on 16 Mar 2020
Hi Alessio,
The mean function will help in this case. Here is the documentation page of mean function having different exampleshttps://www.mathworks.com/help/matlab/ref/mean.html
% Consider a random matrix
a = randn(1000,10000); % Implies 1000 rows and each row containing 10000 columns
% Calculate the mean of each column
meCol = mean(a);
% Calculate the mean of each row
meRow = mean(a,2); % This is your intended case
Hope this helps.
Sriram Tadavarty
Sriram Tadavarty on 16 Mar 2020
Hi Alessio,
In this case, you can run a fop loop on number of rows and take mean for each row.
% Rows variable is a cell array with different number of elements in it. For example
Rows = {[1 4 5],[1 9 10 100]};
for i = 1:numel(Rows)
avg(i) = mean(Rows{i});
% avg returns [3.3333 30.0000] each element corresponding to each row
Hope this helps

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