find values in vector present in cell array

3 vues (au cours des 30 derniers jours)
Elysi Cochin
Elysi Cochin le 17 Mar 2020
Modifié(e) : Andrei Bobrov le 17 Mar 2020
i have a cell array cA and vector V with values
cA = {[11,21,3;14,5,63], [11,22], [33;95;66;7]};
V = [14 22 33 66];
i wanted to find which all values in V are there in cA and its position
output = { [ 0 0 0 1 0 0], [1 2], [3 0 4 0] }

Réponse acceptée

Andrei Bobrov
Andrei Bobrov le 17 Mar 2020
Modifié(e) : Andrei Bobrov le 17 Mar 2020
out = cell(size(cA));
for i = 1:numel(out)
x = cA{i}';
[~,out{i}] = ismember(x(:)',V);
end
or with cellfun
[~,out] = cellfun(@(x)ismember(reshape(x',1,[]),V),cA,'un',0);

Plus de réponses (1)

Ahmed Anas
Ahmed Anas le 17 Mar 2020
Dear, Always use matrix instead of cell arrays, working with matrix is really easy as compared to cell arrays. In the code below, i have split cA matrix into three small matrices and then checked the entities which are present in vector V. Afterwards compile the entire output matrix.
%%Splitting cA matrix into three consistent matrices
cA1 = [11,21,3;14,5,63]
cA2 = [11,22]
cA3 = [33;95;66;7]
V = [14 22 33 66];
%%Checking for entities of cA1
[Lia,Locb1] = ismember(cA1,V)
reshape(Locb1,1,[])
transpose(Locb1)
Locb1.'
Locb1(:)
Locb1=reshape(Locb1.',1,[])
%%Checking for entities of cA2
[Lia,Locb2] = ismember(cA2,V)
Locb2=reshape(Locb2,1,[])
%%Checking for entities of cA3
[Lia,Locb3] = ismember(cA3,V)
Locb3=reshape(Locb3,1,[])
Output=cell2mat({Locb1,Locb2,Locb3})
  2 commentaires
Elysi Cochin
Elysi Cochin le 17 Mar 2020
Modifié(e) : Elysi Cochin le 17 Mar 2020
the dimension of cell array changes. so how to keep the code unaltered for any dimension
sometimes
cA = {[11,22,3;44], [14,22]};
V = [14 22 33 66];
output = { [ 0 2 0 0 ], [1 2] }
Ahmed Anas
Ahmed Anas le 17 Mar 2020
I am unable to understand [11 22 3;44] in cA = {[11,22,3;44], [14,22]};
Its dimensions should be consistent

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