Hi
I want to store data from a nested for loop and this is my code
%%Initialisation 1
delta_x=(2*pi)/100;
delta_y=delta_x;
H=2*pi;
L=4*pi;
%Mesh
n=(L/delta_x)+1; Converts rectangle to a mesh
m=(H/delta_y)+1;
x=[0:delta_x:n]';
y=[0:delta_y:m]';
for i=x(2):delta_x:x(end-1)
for j=y(2):delta_y:y(end-1)
pointer=[(j-1)*n+i];
end
end
Everytime the pointer runs it only gives me the latest iteration and not all the iterations like I want. I tried putting (i,j) before it but that was to no avail and now am at my wits end as to what to do. Any help would be much appreciated

 Réponse acceptée

Adam Danz
Adam Danz le 17 Mar 2020
Modifié(e) : Adam Danz le 17 Mar 2020

0 votes

Give this a shot. It's usually best to set up for-loops to iterate over integer values 1 to n. Those integer values can be used to index input values and store the outputs.
iLoop = x(2):delta_x:x(end-1);
jLoop = y(2):delta_y:y(end-1);
pointer = nan(numel(iLoop), numel(jLoop));
for i = 1:numel(iLoop)
for j = 1:numel(jLoop)
pointer(i,j)=(jLoop(j)-1)*n+iLoop(i);
end
end

3 commentaires

Maaz Madha
Maaz Madha le 18 Mar 2020
thank you so much for this. May I ask what nan(numel(iLoop)...) does as I would like to improve my Matlab knowledge as well
Adam Danz
Adam Danz le 18 Mar 2020
Good question!
This is known as preallocation. My example shows how to store scalar outputs (single value) at location (i,j) in variable 'pointer'. Instead of building that matrix as the loops iterate, the matrix is created with NaN values prior to the loops. This makes the code faster and cleaner.
The numel() function just returns the number of elements of a vector.
Maaz Madha
Maaz Madha le 18 Mar 2020
aah i understand now. Thank you so very much :) have a great day

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