using end in array

I have

 B=[];
A = {[1,2,3,15],[14,15,45,44,38,48,47,46]};
for i=1:length(A)
    for j=1: length(A{i})-1
        temp = A{i};
        B =[B;[temp(j), temp(j+1)]];
        
    end
end

B should be

B =[1,2; 2,3; 3,15; 15,1; 14,15; 15,45; 45,44; 44,38;38,47; 47,46; 46 14];

Answer 1

[Sriram Tadavarty]

Hi Na,

Minor update to your code, will give what you are looking for

B=[];
A = {[1,2,3,15],[14,15,45,44,38,48,47,46]};
for i=1:length(A)
    for j=1: length(A{i})-1
        temp = A{i};
        B =[B;[temp(j), temp(j+1)]];
        
    end
    B = [B; [temp(end), temp(1)]]; % Update this, to get what you are looking for
end

Hope this helps

Regards,

Sriram

[NA]

Thanks, is there any possibility to remove the for loop?

[Sriram Tadavarty]

Yes you could remove the inner for loop

B=[];
A = {[1,2,3,15],[14,15,45,44,38,48,47,46]};
for i=1:length(A)
    temp = [A{i} A{i}(1)];
    B = [B;[temp(1:end-1)' temp(2:end)']];
end

[Sriram Tadavarty]

Hi,

You can even try this

A = {[1,2,3,15],[14,15,45,44,38,48,47,46]};
ATemp = arrayfun(@(x) [A{x} A{x}(1)],1:length(A),'UniformOutput',false);
BTemp = cellfun(@(x) [x(1:end-1)' x(2:end)'],ATemp,'UniformOutput',false)
B = cell2mat(reshape(BTemp,[],1))

Hope this helps.

Regards,

Sriram