Error using *equal* when indexing information for creating a structure

1 vue (au cours des 30 derniers jours)
Amy Hassett
Amy Hassett le 23 Mar 2020
Modifié(e) : Adam Danz le 24 Mar 2020
Hi all,
I am trying to create a structure, by indexing from a cell array (which I define as follows):
Behaviours = {"Wall Jump"; "Move Isolated"; "Rear Isolated"; "SAP";
"Stop Isolated"; "Huddling"; "Contact"; "Move in contact"}
Here is the code for creating the structure:
for k =1:size(Behaviours)
AnimalData(k).behaviour = Behaviours(k);
AnimalData(k).All_Instances = dat(dat.NAME == Behaviours(k), :);
end
I wish to loop through each of these behaviours, and want to make a structure that contains all the information that I have in relation to each of these behaviours. However, when I try to pull the behavioural data from the "dat" structure that contains all my data I get the following error:
Error using == (line 25)
Invalid types for comparison.
Line 25 corresponds to the last line of my "for" loop. If I replace "Behaviours(k), :) with one of my behaviours, I do not get this error.
Can someone tell me what I am doing wrong?
  3 commentaires
Amy Hassett
Amy Hassett le 23 Mar 2020
To give you an idea, here is my dat Table.
Making the changes you recommend, here is the new code:
for k =1:size(Behaviours)
data(k).behaviour = Behaviours(k);
data(k).All_Instances = dat(strcmp(dat.NAME, Behaviours(k)));
end
When I run it, data.All_Instances is just a bunch of empty cells. Any advice?
Adam Danz
Adam Danz le 23 Mar 2020
I continued the discussion in the answers section.

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Réponses (1)

Adam Danz
Adam Danz le 23 Mar 2020
It doesn't look like you applied the recommendation correctly.
strcmp() returns a logical vector identifying which rows are a match. Try this.
data(k).All_Instances = dat(strcmp(dat.NAME, Behaviours(k)),:);
  2 commentaires
Amy Hassett
Amy Hassett le 23 Mar 2020
This gave an empty set, but it did make me think to try this:
for k =1:size(Behaviours)
data(k).behaviour = Behaviours(k);
data(k).All_Instances = dat(dat.NAME == data(k).behaviour, :);
end
Which worked!
Adam Danz
Adam Danz le 23 Mar 2020
Modifié(e) : Adam Danz le 24 Mar 2020
If you attach a mat file containing the dat table, I could take a look at what's happening.
save('datData.mat', 'dat')
Are you sure the variables you're working with are string arrays rather than cell arrays of character vectors?

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