Error using *equal* when indexing information for creating a structure

Hi all,
I am trying to create a structure, by indexing from a cell array (which I define as follows):
Behaviours = {"Wall Jump"; "Move Isolated"; "Rear Isolated"; "SAP";
"Stop Isolated"; "Huddling"; "Contact"; "Move in contact"}
Here is the code for creating the structure:
for k =1:size(Behaviours)
AnimalData(k).behaviour = Behaviours(k);
AnimalData(k).All_Instances = dat(dat.NAME == Behaviours(k), :);
end
I wish to loop through each of these behaviours, and want to make a structure that contains all the information that I have in relation to each of these behaviours. However, when I try to pull the behavioural data from the "dat" structure that contains all my data I get the following error:
Error using == (line 25)
Invalid types for comparison.
Line 25 corresponds to the last line of my "for" loop. If I replace "Behaviours(k), :) with one of my behaviours, I do not get this error.
Can someone tell me what I am doing wrong?

3 commentaires

Adam Danz
Adam Danz le 23 Mar 2020
Modifié(e) : Adam Danz le 23 Mar 2020
What is stored in dat.NAME? Could you show us an example copied from your command window?
Here are some things to fix,
  1. If you're using a string array, use square brackets: ["Wall Jump", ..., "Move in contact"];
  2. When comparing strings or char-arrays, use strcmp() or strcmpi():. strcmpi(dat.NAME, Behaviours(k))
To give you an idea, here is my dat Table.
Making the changes you recommend, here is the new code:
for k =1:size(Behaviours)
data(k).behaviour = Behaviours(k);
data(k).All_Instances = dat(strcmp(dat.NAME, Behaviours(k)));
end
When I run it, data.All_Instances is just a bunch of empty cells. Any advice?
I continued the discussion in the answers section.

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Réponses (1)

It doesn't look like you applied the recommendation correctly.
strcmp() returns a logical vector identifying which rows are a match. Try this.
data(k).All_Instances = dat(strcmp(dat.NAME, Behaviours(k)),:);

2 commentaires

This gave an empty set, but it did make me think to try this:
for k =1:size(Behaviours)
data(k).behaviour = Behaviours(k);
data(k).All_Instances = dat(dat.NAME == data(k).behaviour, :);
end
Which worked!
If you attach a mat file containing the dat table, I could take a look at what's happening.
save('datData.mat', 'dat')
Are you sure the variables you're working with are string arrays rather than cell arrays of character vectors?

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le 24 Mar 2020

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