How to graph using a for loop

I am asking for help in plotting a line graph in my "for" loop program. The program is able to run the calculations but I am not able to graph. Below is the code i have created.

clc
    f=196.2;
    fi=0; finc= pi/180; ff=pi/4
    for x=0:pi/180:pi/4;
    ac= (f*cos(x))/((sin(pi/6)*cos(x))+(cos(pi/6)*sin(x)))
    fprintf('Force of AC is %7.2f\n',ac)
    bc= ((ac*cos(pi/6))/cos(x))
    fprintf('Force of BC is %7.2f\n',bc)
    end
  hold on;
 xx=x(1:length(x));
 plot(xx,ac)

Answer 1

[KSSV]

YOu need not use a loop as the other user has suggested you. If you use a loop, you need to intiilaize the array and save it in a loop as below:

    f=196.2;
    fi=0; finc= pi/180; ff=pi/4 ;
    x=0:pi/180:pi/4; 
    ac = zeros(size(x)) ; 
    for i = 1:length(x)
    ac(i)= (f*cos(x(i)))/((sin(pi/6)*cos(x(i)))+(cos(pi/6)*sin(x(i))))
    fprintf('Force of AC is %7.2f\n',ac)
    bc= ((ac*cos(pi/6))/cos(x(i)))
    fprintf('Force of BC is %7.2f\n',bc)
    end
    plot(x,ac)

[Jose Moreno]

Thanks for the help.

Answer 2

[Sriram Tadavarty]

Hi Jose,

This code need not require a for loop. The following can be done to get the same result:

clc
    f=196.2;
    fi=0; finc= pi/180; ff=pi/4
     x=0:pi/180:pi/4;
    ac= (f*cos(x))./((sin(pi/6)*cos(x))+(cos(pi/6)*sin(x)))
    fprintf('Force of AC is %7.2f\n',ac)
    bc= ((ac*cos(pi/6))./cos(x))
    fprintf('Force of BC is %7.2f\n',bc)
   
 hold on;
 plot(x,ac)

Hope this helps.

Regards,

Sriram

[Jose Moreno]

Thanks a lot this has helped by showing me another way.