How to solve first order ode with two boudary conditions?

I need to solve numericaly differential equation of the first order, where I have given values at the beginng and at the end of time span, it means I have p(t=0) = 0, p(t=1) = 0. My differential equation where p is variable for which I am looking for is:

p' = - ( - 8 .* y' ./ R - y' .* p - 32 .* beta .* k ./ R .^ 4 ) ./ y

and k is also unknown variable, and R, beta, y, y' are known variables

I tryed to solve it and get p with bvp4c, but I found only examples where differential equations of the second order where solved, with conditions in two end points, and it should be like that - for second order equation two conditions.

I was looking ode45 also, but there you can give time span and the conditions at the end of that span, it means I could give only one condition here.

For what I should search for? Did I miss something in this case?

[Torsten]

You miss that k is also unknown. Thus you have two equations: p'=... and k'=0 for which 2 boundary conditions are necessary ( the two for p ).

Search for "solve bvp with unknown parameters & bvp4c" in the internet.

[darova]

Are you sure about all you constants/parameters? Maybe you want to fit some? Look this