Generate matrix at each iteration

Dear friend, please help me to generate a matrix 'yy' which stores matrix "xx" in each iteration.
%% direct search methods
clc;
clear variables;
delta=[2;2];
eps=10^(-3);
%% BOX EVOLUTINARY OPTIMIZATION METHOD
x0=[1;1];
% k=(delta(1)^2+delta(2)^2)^0.5;
for i=1:3
x1=x0+[1;-1];
x2=x0+[-1;-1];
x3=x0+[-1;1];
x4=x0+[1;1];
xx=[x0 x1 x2 x3 x4];
yy=xx();
f(1)=diremtd(x0);f(2)=diremtd(x1);
f(3)=diremtd(x2);f(4)=diremtd(x3);f(5)=diremtd(x4);
A=[f(1),f(2),f(3),f(4),f(5)];
k=min(A);
for j=1:5
if k==f(j)
tt=xx(:,j);
t=f(j);
end
end
x0=tt;
end
THANK YOU

 Réponse acceptée

Image Analyst
Image Analyst le 29 Mar 2020
Instead of
yy=xx();
have
yy{i} = xx;

4 commentaires

DEV
DEV le 29 Mar 2020
dear image analyst
xx is 2*5 matrix.
this correction "yy{i} = xx;" WONT WORK
Why not? It puts the whole array into the i'th cell of a cell array called yy. It should work. You asked "generate a matrix 'yy' which stores matrix "xx" in each iteration" and it certainly does that. Since what you asked is not what you want, what do you want? Do you want yy to be a 3-D array where each xx is one slice in a stack of 3 xx's? If so, declare yy before the loop:
yy = zeros(2, 5, 3);
then inside the loop, insert the current xx into slice i:
yy(:, :, i) = xx;
I can't run your code because I don't know what the diremtd() function or variable is.
DEV
DEV le 29 Mar 2020
dear image analyst
thank you so much i got the matrix :).
Image Analyst
Image Analyst le 30 Mar 2020
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