Need matlab coding for the given c program
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#include <stdio.h>
int main()
{
char a[100];
int i;
i=0;
scanf("%c",&a[i]);
while(a[i]!='$')
{
i++;
scanf("%c",&a[i]);
}
a[i]='\0';
i=0;
while(a[i]!='\0')
{
printf("%c",a[i]);i++;
}
return 0;
}
3 commentaires
darova
le 30 Mar 2020
You are declaring a variable but not assigning any value (no initialization). How should it work?

leo john
le 30 Mar 2020
James Tursa
le 31 Mar 2020
@darova: The scanf line is assigning a value to a[i]
Réponses (2)
darova
le 30 Mar 2020
try this
i = 1;
a{1} = '1';
while ~strcmp(a(i),'&')
str = input('','s');
i = i + 1;
a{i} = str;
end
6 commentaires
leo john
le 31 Mar 2020
leo john
le 31 Mar 2020
darova
le 31 Mar 2020
Use strfind
while ~isempty(strfind((a{i},'&')))
leo john
le 18 Avr 2020
Walter Roberson
le 18 Avr 2020
Note that using input() like that is not the same as the C code. The C code retrieves one character at a time from standard input, and finds the first '$' character, leaving standard input positioned immediately after the '$'. The loop with input() on the other hand does the equivalent of getline() each time and checks whether the input line has at least one '$' character. This is a very different requirement.
Remember, input() with 's' option fetches a line. You store the entire line into a{i}. You then test whether that entire line ~= '$', which is a vector test. The test fails if any element of the vector is 0, which would occur if any element of a{i} did equal '$'
leo john
le 18 Avr 2020
Walter Roberson
le 31 Mar 2020
MATLAB cannot code that. scanf() reads from standard input, but MATLAB does not have standard input.
If you had a fileid of an opened file, then
s = fscanf(fid, '%c%[^$]$', 2);
fprintf('%s', s);
This has the same behaviour as the C code: it extracts at least one character, and up to but excluding a $ character, and consumes the $ character leaving the pointer right after it; and it outputs the extracted string to the display without any newline.
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