fminsearch with part of input function

2 vues (au cours des 30 derniers jours)
franco otaola
franco otaola le 31 Mar 2020
Commenté : franco otaola le 1 Avr 2020
hello,
i have defined a function that is model, and want to use a fminsearch for a first value for the lsqnonlin,but i get all the time "Assignment has more non-singleton rhs dimensions than non-singleton subscripts" also in the error it says fv(:,1) = funfcn(x,varargin{:}); the model_error is the output to optimise
my code:
param0=[1, 50];
param0=fminsearch(@(param) Model(param,t,inlet_signal,outlet_signal),param0);
function [error_model,h]= dispmodel_2param(param,t,x,y)
theta = t/param(2);
h = (sqrt(param(1)./(4*pi*theta)).*exp(-param(1)./(theta*4).*(1-theta).^2));
h(1) = 0;
y=[y;y(end)*zeros((length(E_theta)+length(x)-1)-length(y),1)];
error_model= y-conv(h/param(2),x);
end

Réponse acceptée

Walter Roberson
Walter Roberson le 1 Avr 2020
No matter whether t, inlet_signal and outlet_signal are scalars or vectors, your line
y=[y;y(end)*zeros((length(E_theta)+length(x)-1)-length(y),1)];
is making y into a vector at that point. Then your error_model would be a vector because it involves y.
When you use fminsearch there is a single output for the function, and it must return a scalar.
The form you are using appears to have been designed for use with lsqnonlin, which expects the individual predictions to be returned rather than a sum-of-squares . lsqnonlin internally does the equivalent of sum( (fun(Param) - y).^2 ) but fminsearch does not.
  5 commentaires
Walter Roberson
Walter Roberson le 1 Avr 2020
No, not without using an extra function to capture the extra output and return it instead. It would have to be a true function, not an anonymous function, because of the way that MATLAB deals with additional outputs.
franco otaola
franco otaola le 1 Avr 2020
oh, okey, thanks!

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