Effacer les filtres
Effacer les filtres

Info

Cette question est clôturée. Rouvrir pour modifier ou répondre.

How to generate a loop for the problem mentioned in the context

1 vue (au cours des 30 derniers jours)
Alireza Babaei
Alireza Babaei le 10 Avr 2020
Clôturé : MATLAB Answer Bot le 20 Août 2021
Dear, scholars,
Anybody can help me with writing a decent code for finding the below equation:
I can write the code for the second coefficient of numerator (I mean the following part):
But I can not extend it to the whole equation,
Any ideas?
I attach my code for the second part:
clc
clear all
close all
we = linspace(0,100,101);
gh = [1 3 5];
w = [21 39 88];
for i = 1:3
for j = 1:length(we)
a(i,j) = gh(i) * we(j);
C(i,j) = (1/12)+1i*we(j);
x(i,j) = 12*gh(i);
s3(i,j) = 1i*gh(i)*we(j);
s2(i,j) = w(i)^2 - we(j)^2+1i*w(i);
s1(i,j) = 1i*gh(i)*we(j);
v2(i,j) = s3(i,j)/s2(i,j)+C(i,j);
v1(i,j) = s1(i,j)/s2(i,j);
v(i,j) = abs(v1(i,j)/v2(i,j))
d = log10(sum(v))
d1 = sum(v);
end
end
figure
plot(we,d,'LineWidth',2)
grid on

Réponses (1)

Guru Mohanty
Guru Mohanty le 13 Avr 2020
Hi, I understand you are getting issues in calculating sum of the given expression. You can do this using MATLAB Symbolic Toolbox-
  1. Create symbolic variables using syms.
  2. Build the expression need to be evaluated.
  3. Through an iteration substitute all the variables using subs function. It will output an array.
  4. Finally, Evaluate the summation of the expression using sum function.
Here is a sample code using random values as input.
n=3;
syms s 3
syms C x a
% Create Random Data
av=rand(1,n);
s1_1v=rand(1,n);
s2_1v=rand(1,n);
s3_1v=rand(1,n);
Cv=rand(1,1);
xv=rand(1,n);
% Set Up The Expression
Var=sum(s(1)/s(2))/(C +sum(s(3)/s(2)));
toSum=(Var*x + a)/s(2);
disp(toSum);
for i=1:n
% Substitute Values through Iteration
subSum(i)=subs(toSum,{a , s1_1 , s2_1 , s3_1 , C , x}, ...
{av(i),s1_1v(i),s2_1v(i),s3_1v(i),Cv,xv(i)});
end
OutSum=double(sum(subSum));
disp(OutSum);

Cette question est clôturée.

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by