How to count number of occurences of each value in a vector and put the number beside the value as a new column?
22 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
I have vector (3079X1).
I want to count the number of occurrences of each value within the vector and put that number beside the respective value of the vector. I have tried using groupcount but it reorders the result in ascending order. I want to keep the same order as it was in the original vector.
0 commentaires
Réponses (3)
Stephen23
le 13 Avr 2020
>> V = randi(9,13,1)
V =
6
4
4
2
9
5
1
6
2
1
6
9
4
>> [N,X] = histc(V,unique(V));
>> M = [V,N(X)]
M =
6 3
4 3
4 3
2 2
9 2
5 1
1 2
6 3
2 2
1 2
6 3
9 2
4 3
darova
le 13 Avr 2020
Try this
a = randi(5,20,1);
x = a*0;
[a1,ix] = sort(a); % sort array to see how many duplicates
k = 0;
for i = 1:length(a)-1
if a1(i)~=a1(i+1)
x(k+1:i) = i-k; % write numer of duplicates
k = i; % position of last diplicate
end
end
x(k+1:end) = length(x)-k; % write last portion of duplicates
[~,ix1] = sort(ix); % restore original order
disp('sorted values with number of duplicates')
[a1 x]
disp('original values with numer of duplicates')
[a x(ix1)]
2 commentaires
Walter Roberson
le 14 Avr 2020
You posted that you have a "vector"; it now appears that you have a cell array of some sort. Possibly it is a cell array of character vectors. Possibly it is a cell array of transfer functions. Possibly it is a cell array of function handles. We would need more information to advise you.
Image Analyst
le 13 Avr 2020
Try this:
% Create sample data
v = randi(1000, 3079, 1)
% Now take a histogram:
edges = min(v) : 1 : max(v)+1;
hObject = histogram(v, edges) % Also displays the histogram
grid on;
% Create matrix with v as first column, and count as second column
m = [v, zeros(length(v), 1)];
% Assign the counts to each value.
for k = 1 : length(v)
% Get the value of the vector at this index.
value = v(k);
% Get the counts from the histogram for that value
% and stuff into the second column of m.
m(k, 2) = hObject.Values(value);
end
6 commentaires
Image Analyst
le 14 Avr 2020
I just copied and pasted my code and it ran fine. Moreover, the first argument to min() is a numeric vector -- it's a double. So you must have altered my code somehow. But you forgot to attach your modified script. Please do so if you want me to fix it.
Voir également
Catégories
En savoir plus sur Matrices and Arrays dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!