Using fminbnd to find the max value.

How can I find the max value between 0.5 - 5 using fminbnd?

m=.09
b=2.7
Eq1=@(x)   b.*(x.^m)
% I try this but I get an error
Maxp=fminbnd(Eq1.*-1,0.5,5)

Answer 1

[Walter Roberson]

[Bestx, Maxp] = fminbnd(@(x) -Eq1(x), 0.5, 5)