Generate values with constrains
1 vue (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hamzah Faraj
le 20 Avr 2020
Commenté : Walter Roberson
le 24 Avr 2020
Hello,
I am new to matlab and I would like to generate several temperatures (V)s to cover a time duration (Tmax). Vmin <= V <= Vmax. The initial temperature in the room V(t=0)=V0=0; The temperature (V) can be found using thde function:
V(i)=V(i-1)+A*(t(i)-t(i-1));
"A " is picked randomly from A, but with no direct repetition. For example:
A1, A1, A0 , A2 not acceptable since A1 is followed by A1
A1,A2,A0,A1,A2,A2 not accepted since A2 is followed by A2
A1,A2,A0,A1.A0 accpeted
A1,A0,A1,A0,A1 accepted
The number of schedules =10;
Can someone help me please with writting the code. Here is my model.
%% This code is to generate set of temperatures between vmin and Vmax to cover a given time
%
%-------------------------------------------------------------------------%
clear variables;
close all;ddd
clc;
%------------------------------------------------------------------------%
%% Defining Units
%------------------------------------------------------------------------%
A=[-4 4/3 2];
v0=0; % Initial temperature
t0=0; % Initial time
Tmax=7; % Total time
Vmax=5; % Maximum temperature
Vmin=-1; % Minimum temperature
n=10; % Number of itterations (schedules)
n1=nan;
%-------------------------------------------------------------------------%
for i = 1:n
while t<=Tmax
V(i)=V(i-1)+(randi(A)*(rand-t(i-1)));
if V(i)>Vmax || V<Vmin
V(i)=A*(rand-t);
else
% Do Nothing
end
% To avoid selecting the same A
n2 = ind(A);
while n1 == n2
n2 = randi(A);
end
V(i)= [V, n2];
n1 = n2;
end
end
2 commentaires
Walter Roberson
le 20 Avr 2020
Your random selection can be improved. Generate a random index with
NA - length(A);
i1 = randi(NA);
n1 = A(i1);
After that, you can get a different random entry without direct repetitions by using
i2 = randi(NA-1);
i2 = i2 + (i2 >= i1);
n2 = A(i2);
Réponse acceptée
Plus de réponses (2)
Walter Roberson
le 22 Avr 2020
A=[-4 4/3 2];
n = 10;
NA = length(A);
randA = zeros(1,n);
i1 = randi(NA);
randA(1) = A(i1);
for K = 2 : n
i2 = randi(NA-1);
i2 = i2 + (i2 >= i1);
randA(K) = A(i2);
i1 = i2;
end
0 commentaires
Devineni Aslesha
le 24 Avr 2020
To select a random value from A and to obtain different consecutive A's for every schedule can be done using randperm as well.
for i = 1:2:10
n1 = randperm(length(A));
flag = 0;
if i>1
if n1(1) == n2
n1(1) = n1(2);
flag = 1;
end
end
A1(i) = n1(1);
if flag == 1
n2 = n1(3);
else
n2 = n1(2);
end
A1(i+1) = n2;
end
Here, A1 is the desired output.
1 commentaire
Walter Roberson
le 24 Avr 2020
You never use n1(4) or later so there is no point in using randperm(length(A)): you might as well use randperm(length(A),3)
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!