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how to make the matlab code to test the equation below convergent or divergent?

11 vues (au cours des 30 derniers jours)
Muhammad Rohim
Muhammad Rohim le 21 Avr 2020
Commenté : Ameer Hamza le 21 Avr 2020
below is the matlab code that I used to solve it. but more code is needed to display the convergent or divergent equation above.
function [ Sum_n, series_1 ] = Coba5( n, es )
%Percobaan 3
clc;
clear;
n = input ('nilai signifikan: ');
series_1 = 0
es = 0.5*(10^(2-n));
for ns = 1:100
x = cumsum( sin(2*ns)./ns.^2)
series_1 = series_1 + x
end
disp([es]')
end

Réponses (1)

Ameer Hamza
Ameer Hamza le 21 Avr 2020
Just find the sum and check if it is convergent or divergent
syms n
term = sin(2*n)/n^2;
y = vpa(symsum(term, n, 1, inf));
if isinf(y)
fprintf('divergent\n');
else
fprintf('convergent\n');
end
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