Summation Problem (symsum)

To be honest im not a teacher nor lecturer, im a student having difficulty code some problem about summation (symsum).

What im trying to do is to search for code to make table epsilon_s>epsilon a From the question above.

Epsilon_s = 0,5*10^(2-n)

Heres some code from my previous homework (i got this answer also from this website, shout out to Ameer)

function maclaurin2
term_n = @(x,n) x^n./factorial(n); % formula for n-th term of series
N = 10; % total number of terms we are going to calculate
result = zeros(1,N+1); % initializng a array to save the partial sums
eplison_t = zeros(1,N+1);
eplison_a = zeros(1,N+1);

x = 1/2; % value of x to use in this calculation
result(1) = term_n(x,0); % calculate first term of the series at n=0
eplison_t(1) = (exp(x) - result(1))/exp(x);
for n=1:N % terms n=1,2,...,N
    result(n+1) = result(n) + term_n(x,n); % current partial sum is the addition of last partial sum and the value of n-th term
    eplison_t(n+1) = (exp(x) - result(n+1))/exp(x);
    eplison_a(n+1) = (result(n+1)-result(n))/result(n+1);
end

eplison_t = 100*eplison_t;
eplison_a = 100*eplison_a;

t = table(result', eplison_t', eplison_a');
disp(t)
end

Any form of help will be highly appriciated!

[Jeff Alderson]

Documentation on the symsum command is available here: https://www.mathworks.com/help/symbolic/symsum.html

Unfortunately, we can't help you with answers about specific homework assignments in this forum.

Also, you may want to edit your existing post to remove any screenshots that are showing phone numbers.

[Lockedfield]

Thank you for the reply, actually thats not a phone number