Keep getting "Index exceeds number of array elements (1)" message

1 vue (au cours des 30 derniers jours)
Reem Gawish
Reem Gawish le 21 Avr 2020
Commenté : Reem Gawish le 21 Avr 2020
Hi, I have this code below, which works when I simplify the code to simply add to either x or y arrays, but doesn't work when I'm doing both, can anyone help me figure out why this may be? I'm being told from the error message that there's something wrong with "x(t)=x(t-1)-1;"
x(1)=0;
y(1)=0;
c=clock;
z=c(1,6)*1000;
rand('seed',z);
for i=1:50
r(i)=floor((3-1)*rand(1)+1);
r2(i)=floor((5-1)*rand(1)+1);
end
for t=2:50
if r(t)==1
if mod(r2(t),2)==0
x(t)=x(t-1)+1;
else
x(t)=x(t-1)-1;
end
end
if r(t)==2
if mod(r2(t),2)==0
y(t)=y(t-1)+1;
else
y(t)=y(t-1)-1;
end
end
end
disp(x)
disp(y)
  2 commentaires
Toey
Toey le 21 Avr 2020
Modifié(e) : Toey le 21 Avr 2020
Hi Reem,
In your code, x & y only increase their sizes when r(t)==1 and r(t)==2, but your index t increases by 1 every loop. This is when there's mismatch between indexing and the size of x,y.
To fix the issue, you can preallocate x,y in the beginning of your code
x=zeros(50,1); y=zeros(50,1);
or having x(t) =0 in the else statement when r(t)==1 isn't met.
Reem Gawish
Reem Gawish le 21 Avr 2020
Just tried this and got it working! Thanks so much!

Connectez-vous pour commenter.

Réponse acceptée

Sriram Tadavarty
Sriram Tadavarty le 21 Avr 2020
Hi Reem,
Make minor modification to the code to avoid that error as shown below:
x(1)=0;
y(1)=0;
c=clock;
z=c(1,6)*1000;
rand('seed',z);
for i=1:50
r(i)=floor((3-1)*rand(1)+1);
r2(i)=floor((5-1)*rand(1)+1);
end
for t=2:50
if r(t)==1
if mod(r2(t),2)==0
x(t)=x(t-1)+1;
else
x(t)=x(t-1)-1;
end
else
x(t) = 0; % Added this to ensure that value is stored as zero, when r(t) is not equal to 1
end
if r(t)==2
if mod(r2(t),2)==0
y(t)=y(t-1)+1;
else
y(t)=y(t-1)-1;
end
else
y(t)=0; % Added this to ensure that value is stored as zero, when r(t) is not equal to 2
end
end
disp(x)
disp(y)
Hope this helps.
Regards,
Sriram
  1 commentaire
Reem Gawish
Reem Gawish le 21 Avr 2020
Thanks so much for your help! Finally understood what the problem was lol

Connectez-vous pour commenter.

Plus de réponses (0)

Catégories

En savoir plus sur Matrix Indexing dans Help Center et File Exchange

Tags

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by