How would one write their own polyfit function using only mldivide and for loops?
I have a basic idea:
function [A,e] = MyPolyRegressor(x, y, n)
c=ones(n,1);
for i=1:n;
c(:,i)=x.^(i-1);
end
A=c\y
e=c*A-y
But it doesnt quite work.

3 commentaires

Jan
Jan le 26 Oct 2012
Modifié(e) : Jan le 26 Oct 2012
Please explain what "doesn't quite work" mean explicitly. Do you get an error message or do the results differ from your expectations? This forum is fine for solving problem, but bad for guessing them.
Notes: The POWER operation is very expensive. Better multiply x cummulatively.
SB
SB le 26 Oct 2012
Well, there's a dimension mismatch in line 4. Even when I switch c to c=ones(size(X)) to fix that issue, there are too many coefficients, none of which are correct.
Jan
Jan le 26 Oct 2012
Modifié(e) : Jan le 26 Oct 2012
Because you didn't format your code properly (please learn how to do this...), it is not possible to find out, which one is the "line 4".
But with some guessing: "ones(n,1)" and even "ones(size(x))" create vectors, while the required Vandermonde-matrix needs the dimensions [length(x), n+1].

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 Réponse acceptée

Jan
Jan le 26 Oct 2012
Modifié(e) : Jan le 26 Oct 2012

4 votes

function p = fPolyFit(x, y, n)
% Construct Vandermonde matrix:
x = x(:);
V = ones(length(x), n + 1);
for j = n:-1:1
V(:, j) = V(:, j + 1) .* x;
end
% Solve least squares problem:
[Q, R] = qr(V, 0);
p = transpose(R \ (transpose(Q) * y(:)));
% Equivalent: (V \ y)'

1 commentaire

SB
SB le 26 Oct 2012
Modifié(e) : SB le 26 Oct 2012
For a weighted Least Squares problem, would you do function [A, e] = WeightedLeastSquares(X, Y, w,n)
X=diag(w)*X
Y=diag(w)*Y
X = X(:);
V = ones(length(X), n + 1);
for j = n:-1:1
V(:, j) = V(:, j + 1) .* X;
end
[Q, R] = qr(V, 0);
A= (R \ (transpose(Q) * Y(:)));
e= V*A-Y;
?

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Plus de réponses (1)

Vrushabh Bhangod
Vrushabh Bhangod le 19 Mai 2018
Modifié(e) : Walter Roberson le 10 Juin 2018

1 vote

function [p,mu,f] = plofit(x,y,n)
% x = input samples
% y = output function,n = order
m = length(x); %number of rows in the Vandermonde Matrix
V = zeros(m,n);
a = n;
for i = 1:m
v = zeros(1,n);
for j = a:-1:1
v(n+1-j) = realpow(x(i),j);
end
V(i,:) = v;
end
V(:,n+1)=ones(m,1);% adding 1 column to ones to the vandermonde matrix
%%QR method to compute the least squares solution for the coefficients,'p'
[Q,R] = qr(V,0);
p = transpose(R \ (transpose(Q) * y'));
f = polyval(p,x);
%%to find mean
mean = sum(x)/length(x);
sq = 0;
for i =1:length(x)
sq = sq + (x(i)-mean)^2;
end
sd = (sq/length(x))^0.5;
mu = [mean;sd];
end

Question posée :

SB
le 26 Oct 2012

Commenté :

Max
le 20 Août 2022

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