Error when adding multiple legends to graph

16 vues (au cours des 30 derniers jours)
birdnerd007
birdnerd007 le 25 Avr 2020
Commenté : Star Strider le 25 Avr 2020
Hello, I am trying to get a legend for the 10 tests I performed, but I am getting the error:
Error using legend (line 279)
Invalid argument. Type 'help legend' for more information.
This is my code:
xposition=(1:4:40);
yposition=zeros(length(xposition),1)+20;
pointsize = 15;
scatter(xposition, yposition, pointsize, HIT, 'filled')
axis([0,40, 0,40]);
grid on
colorbar
colormap("jet")
barnone=colorbar;
set(get(barnone,'Title'),'String','Hardness')
xlabel('X Axis Position (µm)')
ylabel('Y Axis Position (µm)')
q=[HIT(1);HIT(2);HIT(3);HIT(4);HIT(5);HIT(6);HIT(7);HIT(8);HIT(9);HIT(10)];
legend(q,'Test 1', 'Test 2', 'Test 3','Test 4', 'Test 5', 'Test 6', 'Test 7','Test 8', 'Test 9', 'Test 10');
What am I doing incorrectly? Thanks for your help!
  7 commentaires
birdnerd007
birdnerd007 le 25 Avr 2020
dqb - That's exactly what I'm looking for; just one issue, only one blue dot appears as opposed to each of the colors corresponding to each test.
Walter - my apologies, I am still learning this stuff. I was hoping when I used the legend feature and calling my hardness, that it would allow me to name each test in the array. Again, I am probably not making sense because I still learning. Thanks for understanding.
birdnerd007
birdnerd007 le 25 Avr 2020
dqb - Do you know how I can get each color of dot to correspond with Test 1, Test, 2, etc? I appreciate your help.

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Réponse acceptée

Star Strider
Star Strider le 25 Avr 2020
The only way to do what you want is to plot each ‘HIT’ value individually in a for loop:
hold on
for k = 1:numel(HIT)
q(k) = scatter(xposition(k), yposition(k), pointsize, HIT(k), 'filled');
end
hold off
then this works:
legend(q,'Test 1', 'Test 2', 'Test 3','Test 4', 'Test 5', 'Test 6', 'Test 7','Test 8', 'Test 9', 'Test 10', 'Loccation','N', 'NumColumns',2)
  2 commentaires
birdnerd007
birdnerd007 le 25 Avr 2020
You've been absolutely amazing today! Thanks for all of your help. I'm learning so much. Thank you again.
Star Strider
Star Strider le 25 Avr 2020
As always, my pleasure!

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