How can I substitute a variable given by a struct?
4 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Abner Ojeda
le 2 Mai 2020
Commenté : Abner Ojeda
le 3 Mai 2020
Hey, everyone. I'm trying to solve an optimization problem without the Optimization toolbox. I already have the roots from the equation (by "solve"), it gives to me an struct array, with fields x1, x2... xn, my problem is I already have an x1, x2... xn. I've been trying by so many ways but simply I couldn't solve it, I'm looking to asign the value of the fields to the syms variables and then apply "subs". Code below.
Thanks in advance for help. :)
clear; close all; clc;
var= input ('Dimention of domain');
syms x [1 var];
func= input ('Enter the function, i.e [x1+x2+...+xn]: \n');
y=[];
for s=x(1:end)
dp= diff (func, [s]);
y=[y, dp];
end
pc=solve (y);
pucr= fieldnames (pc);
for i= 1:numel(pucr)
vals(i, 1)= getfield(pc,pucr{i});
end
Hf=hessian (func);
Hff= subs (Hf);
2 commentaires
darova
le 2 Mai 2020
Try this
for i= 1:numel(pucr)
v = getfield(pc,pucr{i});
v1 = subs(v,oldv, newv);
vals(i, 1) = doulbe(v1);
end
Réponse acceptée
Walter Roberson
le 2 Mai 2020
subs(ExpressionToSubstituteInto, pc)
When pc is a struct with field names, then the corresponding variable names will have the appropriate values substituted.
Note: this will not work if any of the field names contain an empty value, even if the corresponding variable is not used in the expression. In particular, if you happened to do
pc = solve(y, 'returnconditions', true)
then pc.parameters would be created even if no parameters were generated, and with pc.parameters being empty, subs() with pc would fail. You can get it working by removing the empty field from the struct.
Plus de réponses (0)
Voir également
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!