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MATLAB Onramp: 8.1 Obtaining help

6 vues (au cours des 30 derniers jours)
Jigyasu Chand
Jigyasu Chand le 4 Mai 2020
Hi folks!
I just started exploring MATLAB and I am stuck at the following place. In the course "MATLAB Onramp" which is one of the 'Getting Started' courses, I am not able to get the solution of '8. Obtaining help - Further Practice'. The task is to create a matrix that
  • Contains random integers in the range from 1 to 20,
  • Has 5 rows, and
  • Has 7 columns.
matrix with normally distributed numbers (instead of uniformly distributed numbers).
Please help on this one.
Thanks in advance!

Réponse acceptée

Guillaume le 4 Mai 2020
I've just discovered that there are several versions of the Onramp course (R2018b, R2019a, and R2019b). The last two have slightly different presentation for the assignment (the first one doesn't seem to work properly) but in neither of them do I see that assignment under further practice. Which version are you using (look at the url)? Perhaps it is also language specific.
The assignment doesn't make sense and certainly won't be answered by the doc. You could rescale and recentre a normal distribution and possibly round it to integers but it still wouldn't be restricted to a range. And you could hardly call the result a normal distribution anymore.
You should report it as a bug to mathworks.
  3 commentaires
Guillaume le 4 Mai 2020
I should have read the further practice in more details. I didn't see that "Search the documentation to recreate the same matrix with normally distributed numbers (instead of uniformly distributed numbers)." It's new in the 2019b assignment.
I think it's poor wording, you're supposed to find a function that creates a normally distributed matrix with the same 5x7 dimensions. However, the integers in the range from 1 to 20 is not part of the new requirement.
Basically, they want you to find in the doc the function that creates normally distributed random numbers.
I'll raise a service request to get Mathworks to review the wording.
Jigyasu Chand
Jigyasu Chand le 8 Mai 2020
That seems fair. Thanks a lot!

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Plus de réponses (3)

Abubakr Eltayeb
Abubakr Eltayeb le 14 Août 2020
x = randn([5 7])

Anand Gopal
Anand Gopal le 19 Jan 2021
x = randi([1,20],5,7)

Yillak Gedamu
Yillak Gedamu le 28 Mar 2022
x = randi(20,5,7)


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