I want to make a function that plots 3D quadratic surface
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I want to creat a function that returns a graph of hyperbolic paraboloid just by entring the coefficient of x^2,y^2 and z
function hyperbolicparaboloid(A,B,C)
A=input('enter coeffecient of x^2');
B=input('enter coeffecient of y^2');
C=input('enter coeffecient of z');
%y^2/b^2-x^2/a^2=z/c
%where B=1/b^2, A=1/a^2, C=1/c
X=linspace(-10,10,100);
Y=linspace(-10,10,100);
Z=linspace(-10,10,100);
[X,Y]=meshgrid(X,Y);
Z=((Y.^2*B)-(X.^2*A))./C;
mesh(X,Y,Z);
view([130,30])
end
Althoug the code is working the function cannot be created 
so what is the problem with this function?
1 commentaire
  Walter Roberson
      
      
 le 9 Mai 2020
				What is the point of accepting three input parameters and then promptly ignoring them? You should either have your function not accept any parameters or else you should have your function use the A, B, C values passed in.
Z=linspace(-10,10,100);
That statement is not productive: you overwrite the Z you create there.
Réponses (1)
  rajat aggarwal
      
 le 18 Mai 2020
        
      Modifié(e) : rajat aggarwal
      
 le 18 Mai 2020
  
      You can use ezplot to draw hyperbolic paraboloid 
following links can also help 
clc;
clear all;
[X,Y,Z] = meshgrid(-10:0.5:10,-10:0.5:10,-10:0.5:10);
a=1;
b=1;
c=1;
V = X.^2/a^2 + Y.^2/b^2 - Z.^2/c^2;
p=patch(isosurface(X,Y,Z,V,1)); % This is the key step. It involves getting the part of the volume corresponding to the surface defined by the equation
set(p,'FaceColor','red','EdgeColor','none');
daspect([1 1 1])
view(3);
camlight
1 commentaire
  Walter Roberson
      
      
 le 18 Mai 2020
				Note that ezplot() is not recommended anymore. It uses older technology to create the plot. fplot() is a better choice in most cases now.
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