Plot some part of a correlation matrix
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I need help please as I have the following correlation matrix, and would like to plot only the lower left part as the upper part is just a mirror of the upper part. As bellow:

I used the following command:
% your example code
Fields = [1, 4, 5];
Fields_time = Fields +16;
MT_All = rand(100,26);
% MT_All = rand(100,9);
VariableNames={'sigma','sigma','sigma','tau','tau','tau','mNPV'}; % changed to ensure valid syntax
Mat_All_1_4_5 = [MT_All(:,Fields), MT_All(:,Fields_time), MT_All(:,end-1)];
figure
c = corrplot(Mat_All_1_4_5, 'varNames', VariableNames);
% get current figure handle
fh = gcf;
% find x and y label strings that are not empty within subplots
yLabelN = find(cell2mat(arrayfun(@(dIn)~isempty(dIn.YLabel.String),fh.Children,'UniformOutput',false)));
xLabelN = find(cell2mat(arrayfun(@(dIn)~isempty(dIn.XLabel.String),fh.Children,'UniformOutput',false)));
% rename y labels
for ik = 1:length(yLabelN)
if ik <= 3
fh.Children(yLabelN(ik)).YLabel.String = sprintf('\\sigma_{%d}',Fields(ik));
fh.Children(xLabelN(ik)).XLabel.String = sprintf('\\sigma_{%d}',Fields(ik));
elseif ik <=6
fh.Children(yLabelN(ik)).YLabel.String = sprintf('\\tau_{%d}',Fields(ik-3));
fh.Children(xLabelN(ik)).XLabel.String = sprintf('\\tau_{%d}',Fields(ik-3));
else
fh.Children(yLabelN(ik)).YLabel.String = sprintf('m_{NPV}');
fh.Children(xLabelN(ik)).XLabel.String = sprintf('m_{NPV}');
end
end
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Plus de réponses (1)
Jancoba Dorley
le 26 Mai 2020
0 votes
Hi Yaser, I ran into similar issues and I was able to create a simple fix with help from Matlab tech. See an example with the 'corrplot' data in matLab:
Before (using only corrplot()):
load Data_Canada; %this is an inbuilt dataset
corrplot(DataTable)

Apply the following script:
figure;
[Cr, ~, h] = corrplot(DataTable);
% Find the index to remove the upper triangular part alone, this might
% be different for you base on you data but you can manually import the indexes
% or change the conditions in tril and find
t = tril(Cr, -1) > 0;
mirrors = find(t == 1);
% delete the unnecessary subplots
for i=1:size(mirrors)
delete(subplot(5,5,mirrors(i)));
end
Result

Hope this helps.
1 commentaire
Tomas Salvadores Viertel
le 8 Mai 2022
Hello Jancoba, thanks for posting this, it was quite useful!
The code you provided has a little bug when there are negative correlations in the data. Making the following modification fixes the issue.
t = abs(tril(Cr, -1)) > 0;
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