Create a vector with for loop with mathematical operations
2 vues (au cours des 30 derniers jours)
Afficher commentaires plus anciens
Hasan Berke Bankoglu
le 10 Mai 2020
Commenté : Stephen23
le 23 Jan 2022
w=[5 4 3 2]
Use this vector in a mathematical expression to create the following vectors:
My code snippet is below, code for that question. When I run it, I can't get expected result. I just want to create a vector as noted above.How can I solve that question?
w=[5 4 3 2]
for i= w
a3=[1/(i+i)]
b3 =[i^i]
c3 =[i/sqrt(i)]
d3 =[(i^2)/(i^i)]
end
0 commentaires
Réponse acceptée
KSSV
le 10 Mai 2020
Read about ., element by element operations.
w = [5 4 3 2] ;
a = 1./(w+w) ;
b = w.^w ;
c = w./sqrt(w) ;
d = w.^2./w.^w ;
Plus de réponses (1)
Toder
le 10 Mai 2020
To fix your current code, you need to use indices in the for loop.
w=[5 4 3 2]
for i = w
a3(6-i)=[1/(i+i)]
b3(6-i) =[i^i]
c3(6-i) =[i/sqrt(i)]
d3(6-i) =[(i^2)/(i^i)]
end
This assigns a3(1) in the first loop, a3(2) in the second, etc. Your code reassigns the scalar a3 each loop. The indices I use are somewhat strange because we're looping over w, which is fine, it just makes indices harder to keep track of. You could do it differently by using a counter:
w=[5 4 3 2]
j = 1
for i = w
a3(j)=[1/(i+i)]
b3(j) =[i^i]
c3(j) =[i/sqrt(i)]
d3(j) =[(i^2)/(i^i)]
j = j+1
end
Or you could have your for loop count from 1 to 4:
w=[5 4 3 2]
for i = 1:4
a3(i)=[1/(w(i)+w(i))]
b3(i) =[w(i)^w(i)]
c3(i) =[w(i)/sqrt(w(i))]
d3(i) =[(w(i)^2)/(w(i)^w(i))]
end
All this being said, I recommend "vectorizing" your code where possible. Dot operators perform arithmetic element-by-element, see the documentation for dot multiplication here. For instance, the whole a3 vector can be defined this way:
a3 = 1./(2*w)
5 commentaires
Voir également
Catégories
En savoir plus sur Loops and Conditional Statements dans Help Center et File Exchange
Produits
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!