I need to split sequance of binary numbers to groups with step log2m
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Mostafa Salah
le 14 Mai 2020
Modifié(e) : Ameer Hamza
le 16 Mai 2020
I need to split sequance of binary numbers to groups with step log2m
for example i need to let user input sequance of bits in array then this squance divide into groups with step log2m and each group tansfer to decimal and put them in array again
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Ameer Hamza
le 14 Mai 2020
Run this example
x = '100100111100001111';
m = 8;
n = floor(log2(m));
x = [repmat('0', 1, ceil(numel(x)/n)*n-numel(x)) x]; % pad values so that digits
% can be evenly divided in
% groups of m
x = reshape(x, n, []).';
y = bin2dec(x)
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Ameer Hamza
le 16 Mai 2020
Modifié(e) : Ameer Hamza
le 16 Mai 2020
while true
num = input('please input number of values you need to enter: ');
if isnumeric(num) && round(num)==num % check if it is integer
break;
else
fprintf('Value must be an integer\n');
end
end
x = zeros(1, num);
for i=1:num
while true
xii = input('Input value [0 or 1]: ');
if isnumeric(xii) && any(xii==[0 1]) % check if it is integer
break;
else
fprintf('Value must be 0 or 1\n');
end
end
x(i)=xii;
end
m = 8;
n = floor(log2(m));
% pad zeros so that length become multiple of n
if ~(round(numel(x)/n)==numel(x)/n)
x = [zeros(1, ceil(numel(x)/n)*n-numel(x)) x]; %
end
x = reshape(x, n, []).';
y = x*(2.^(n-1:-1:0)).';% multiply with [2^(n-1) 2^(n-1) ... 2^1 2^0] to convert binary to decimal
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