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I want to shift a part of a row vector to the right then adding a number before the shifted part

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Mohamed Salah
Mohamed Salah on 15 May 2020
Edited: Mehmed Saad on 17 May 2020
assuming I have
a=[1 2 3 4 0 0];
b=[0 0 1 0]
I want 'a' to be
a=[1 2 3 1.5 4 0]
the 1.5 is half the element before
and b indicates when does the shift occur

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Mehmed Saad
Mehmed Saad on 15 May 2020
Edited: Mehmed Saad on 15 May 2020
if b contains only 1 shift
ind = find(b);
a(ind+1:end)=circshift(a(ind+1:end),1);
a(ind+1) = a(ind)/2;
a =
1.0000 2.0000 3.0000 1.5000 4.0000 0

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Mohamed Salah
Mohamed Salah on 15 May 2020
a=[1 2 3 4 5 6 0 0 0 0]; %I always have number of zeros on the right equals the number of shifts
b=[1 1 1 1];
So 'a' should look like
a=[1, 0.5, 2, 1, 3, 1.5, 4, 2, 5, 2.5, 6]
'a' can be around 60 element and so is 'b'
Mehmed Saad
Mehmed Saad on 17 May 2020
Instead of padding zeros at the end of vector a use the following strategy
  1. Donot pad zeros at the end of a
  2. pad zeros in b such that length of a is equal to length of b
  3. replace all the zeros in b with NaN
  4. repeat a in 2nd dimension for example if a is [1 2] then after repeating it in 2nd dimension it will be [1 2;1 2]
  5. multiply 2nd row(repeated) with b and divide it by 2
  6. remove all the NaNs and remaining part will be your answer
a = [1 2 3 4 5 6];
b = [1 1 1 1];
b = [b zeros(1,length(a)-length(b))]; %Making a and b equal in length
b(b==0) = nan;% replacing all zeros in b with NaNs
a = repmat(a,2,1);% repeating the vector array across 2nd dimension
a(2,:) = (a(2,:).*b)/2;% multiplying 2nd row with b and dividing it by 2
a=a(~isnan(a))% index elements which are with out NaNs
The value of a will be
a =
1.0000 0.5000 2.0000 1.0000 3.0000 1.5000 4.0000 2.0000 5.0000 6.0000
similarly for
a = [ 1 2 3 4 0];
b = [0 1 0 0];
Result will be
a =
1.0000 2.0000 3.0000 1.5000 4.0000 0
Hope this works

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