Hi guys, can anyone help me with this please. Thanks.
So i have this Excel file. I filtered a column and then did some operations on the filtered data .
in the end, I wanna create a new matix, A, with the following characteristics. The matrix should have dimension: partID rows* 5 columns. First colum should contain the partID number (from 3 to 15), second column should contain the value of M associated with the partID, third column S, fourth m and fifth s.
how do i build A inside the cycle?

6 commentaires

Turlough Hughes
Turlough Hughes le 15 Mai 2020
Can you share the file?
Murstoe
Murstoe le 15 Mai 2020
thanks you, Here is the file excel.
Turlough Hughes
Turlough Hughes le 23 Mai 2020
Murstoe, it's bad form to remove your question after being given an answer. Can you put it back?
Original question from Google Cache:
"Building a matrix inside a for loop"
Hi guys, can anyone help me with this please. Thanks.
So i have this Excel file. I filtered a column and then did some operations on the filtered data .
in the end, I wanna create a new matix, A, with the following characteristics. The matrix should have dimension: partID rows* 5 columns. First colum should contain the partID number (from 3 to 15), second column should contain the value of M associated with the partID, third column S, fourth m and fifth s.
how do i build A inside the cycle?
xlsData = xlsread('PartS_all.csv');
partID=xlsData(:,4);
for partID=3:15
tenpm=xlsData(xlsData(:,4)==partID,:);
part=sortrows(tenpm, 2); %Sort second column
M(partID)=mean(part(:,8));
S(partID)=std(part(:,8));
m(partID)=mean(part(:,11));
s(partID)=std(part(:,11));
A=
end
Murstoe
Murstoe le 23 Mai 2020
Guys I’m so sorry I don’t know what happened to it. I will sure fix it. I apologise again
Rena Berman
Rena Berman le 1 Juin 2020
(Answers Dev) Restored edit

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 Réponse acceptée

Turlough Hughes
Turlough Hughes le 16 Mai 2020
Modifié(e) : Turlough Hughes le 16 Mai 2020
You could do it as follows:
xlsData = xlsread('PartS_all.xlsx');
partID = xlsData(:,4);
uPartID = unique(partID).'; % Unique part IDs
% Preallocate space
c = 0;
A = zeros(numel(uPartID),5);
for currPartID = uPartID
c = c+1;
part = xlsData(xlsData(:,4) == currPartID,:); %edit
A(c,:) = [currPartID mean(part(:,8)) std(part(:,8)) mean(part(:,11)) std(part(:,11))];
end

2 commentaires

Murstoe
Murstoe le 16 Mai 2020
I get the following error:
Index in position 2 exceeds array bounds (must not exceed 1).
Error in Untitled (line 25)
A(c,:) = [currPartID mean(part(:,8)) std(part(:,8)) mean(part(:,11)) std(part(:,11))];
Turlough Hughes
Turlough Hughes le 16 Mai 2020
I made a mistake. It should work fine now.

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