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getting error as integralParseArgs

5 vues (au cours des 30 derniers jours)
nikhil
nikhil le 16 Mai 2020
Commenté : nikhil le 16 Mai 2020
Hi all,
i am trying to solve the above equation in matlab, but when i am trying to substitute the alp values and x1 values in code and i am getting an error as matrix dimensions must agree while solving the code
any suggestions and thanks in advance
clc;
clear;
format short
ro= 17.5; R = 65; %polar boss opening radius and radius of cylinder
wa= asind(ro/R); b= 1.225*ro; % winding angle
x = b:5:R;
y = ro:0.45:b;
x1 = x/R;
y1 = y/R;
alp = asind(ro./x); alp1 = asind(ro./y);
i = zeros(size(alp));
j= zeros(size(x1));
for c = 1:numel(alp,x1)
func1= @(x)((cosd(wa).*(x.^3))./((sqrt(1-(x.^3))).*((cosd(wa)*cosd(wa)).*((x.^2).*(1+(x.^2)))-(sind(alp).*sind(alp)))));
i(c) = integral(func1,1,alp(c),x1(c));
end

Réponse acceptée

Ameer Hamza
Ameer Hamza le 16 Mai 2020
Which variable represent ρ is not clear. Also, the syntax for calling integral is incorrect. Try this code
clc;
clear;
format short
ro= 17.5; R = 65; %polar boss opening radius and radius of cylinder
wa= asind(ro/R); b= 1.225*ro; % winding angle
x = b:5:R;
y = ro:0.45:b;
x1 = x/R;
y1 = y/R;
alp = asind(ro./x); alp1 = asind(ro./y);
i = zeros(size(alp));
j= zeros(size(x1));
for c = 1:numel(alp)
func1= @(x)((cosd(wa).*(x.^3))./((sqrt(1-(x.^3))).*((cosd(wa)*cosd(wa)).*((x.^2).*(1+(x.^2)))-(sind(alp(c)).*sind(alp(c))))));
i(c) = integral(func1,1,x(c));
end
  5 commentaires
Ameer Hamza
Ameer Hamza le 16 Mai 2020
There seems to be some problem with the limits of integration or the function itself. If you plot the denominator in the limit of integration, you get the following curve
figure
den = @(y) ((sqrt(1-(y.^3))).*((cosd(wa).*cosd(wa)).*((y.^2).*(1+(y.^2)))-(sind(alp1(d)).*sind(alp1(d)))));
a1 = linspace(y(1)/65, 1, 1000);
a2 = den(a1);
plot(a1, a2);
As you can see, the curve passes through y=0, which means that it has a singularity at that point, which might make the integral diverge. You need to figure out how to avoid this singularity.
nikhil
nikhil le 16 Mai 2020
Thanks sir for your suggestion and time

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