How can i write 2D longest character array ?
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Oblique
le 16 Mai 2020
Commenté : Image Analyst
le 16 Mai 2020
This array must be between two asterisk signs (*) and the code should give us the longest name in this array
For example: {'878*jhon*23 ; '*jonathan*87' ; '485*will*421'}
output will be as a 'jonathan'
I wrote code like this. but it's not what want.
a = {'23*Ali*36' ; 'Veli*178' ; '99*Zeynep*'} ;
for k=1:length(a)
val(k)=length(a{k});
x = findstr(a) , '*' )
end
out=a(val==max(val)
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Image Analyst
le 16 Mai 2020
Modifié(e) : Image Analyst
le 16 Mai 2020
Did you just try a super obvious brute force approach using a for loop:
a = {'23*Ali*36' ; 'Veli*178' ; '99*Zeynep*'} ;
nameLengths = zeros(length(a), 3); % Preallocate.
for k = 1 : length(a)
thisCellContents = a{k};
starLocations = find(thisCellContents == '*') % Find indexes of stars.
% Extract the name
if length(starLocations) >= 2
% Extract length between start #1 and star #2.
nameLengths(k, :) = [starLocations(1), starLocations(2), starLocations(2) - starLocations(1) + 1];
elseif length(starLocations) >= 1
% One star. Start from the beginning.
nameLengths(k, :) = [1, starLocations(1), starLocations(1)];
else
% No stars.
nameLengths(k, :) = [1, length(thisCellContents), length(thisCellContents)]; % The whole thing.
end
end
nameLengths % Report to command window.
[maxLength, row] = max(nameLengths(:,3)) % Find the longest one - biggest separation.
longestRow = a{row} % Get the entire string, including the start.
% Extract the substring.
out = longestRow(starLocations(1) + 1 : starLocations(2) - 1)
I'm sure there are less obvious, but more cryptic methods that are shorter if you want to wait for one from someone else.
4 commentaires
Image Analyst
le 16 Mai 2020
You're welcome. Because comments are SO important, I added a few to make it even easier to follow. I encourage you to use descriptive variable names and lots of comments in your code. If my answer helped you maybe you could click the Vote button. Thanks in advance.
Plus de réponses (1)
Ameer Hamza
le 16 Mai 2020
Modifié(e) : Ameer Hamza
le 16 Mai 2020
Try this
a = {'23*Ali*36' ; 'Veli*178' ; '99*Zeynep*'} ;
m = regexp(a, '[A-Za-z]*', 'match');
m = [m{:}];
[~, idx] = max(cellfun(@numel, m));
longest_name = m{idx};
Result
>> longest_name
longest_name =
'Zeynep'
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